Given a square matrix of order n*n, you have to interchange the elements of both diagonals.
Examples :
Input : matrix[][] = {1, 2, 3,
4, 5, 6,
7, 8, 9}
Output : matrix[][] = {3, 2, 1,
4, 5, 6,
9, 8, 7}
Input : matrix[][] = {4, 2, 3, 1,
5, 7, 6, 8,
9, 11, 10, 12,
16, 14, 15, 13}
Output : matrix[][] = {1, 2, 3, 4,
5, 6, 7, 8,
9, 10, 11, 12,
11, 14, 15, 16}
Explanation : Idea behind interchanging diagonals of a square matrix is simple. Iterate from 0 to n-1 and for each iteration you have to swap a[i][i] and a[i][n-i-1].
Javascript
<script>// Javascript program to interchange // the diagonals of matrixlet N = 3;// Function to interchange diagonalsfunction interchangeDiagonals(array){ // swap elements of diagonal for (let i = 0; i < N; ++i) if (i != parseInt(N / 2)) { let temp = array[i][i]; array[i][i] = array[i][N - i - 1]; array[i][N - i - 1] = temp; } for (let i = 0; i < N; ++i) { for (let j = 0; j < N; ++j) document.write(" " + array[i][j]); document.write("<br>"); }}// Driver Code let array = [[4, 5, 6], [1, 2, 3], [7, 8, 9]]; interchangeDiagonals(array);// This code is contributed by subham348.</script> |
Output:
6 5 4 1 2 3 9 8 7
Time Complexity: O(N*N), as we are using nested loops for traversing the matrix.
Auxiliary Space: O(1), as we are not using any extra space.
Please refer complete article on Program to Interchange Diagonals of Matrix for more details!
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