The task is to check whether an array is a subset of another array with the help of JavaScript. There are a few approaches, we will discuss below:
Approaches:
Approach 1: Using JavaScript array.every() method
This approach checks whether every element of the second array is present in the first array or not.
Example: This example uses the approach discussed above.Â
Javascript
// Creating 2 arrayslet arr1 = ["GFG", "Geeks", "Portal",            "Geek", "GFG_1", "GFG_2"];             let arr2 = ["GFG", "Geeks", "Geek"];Â
// Funtion to check subarrayfunction GFG_Fun() {Â Â Â Â let res = arr2.every(function (val) {Â Â Â Â Â Â Â Â return arr1.indexOf(val) >= 0;Â Â Â Â });Â
    let not = "";    if (!res) {        not = "not";    }    // Display the output    console.log("Array_2 is " + not         + " the subset of Array_1");}Â
GFG_Fun(); |
Output
Array_2 is the subset of Array_1
Approach 2: Using JavaScript array.some() method
This approach declares false if some element of the second array is not present in the first array.
Example: This example uses the approach discussed above.Â
Javascript
// Create input arrayslet arr1 = ["GFG", "Geeks", "Portal", Â Â Â Â Â Â Â Â Â Â Â Â "Geek", "GFG_1", "GFG_2"];Â
let arr2 = ["GFG", "Geeks", "GeekForGeeks"];Â
// Function to check subarraysfunction GFG_Fun() {    let res = !arr2.some(val => arr1.indexOf(val) === -1);    let not = "";    if (!res) {        not = "not";    }         // Display output    console.log("Array_2 is " + not         + " the subset of Array_1");}Â
GFG_Fun(); |
Output
Array_2 is not the subset of Array_1
