Given two sorted arrays of distinct elements, we need to print those elements from both arrays that are not common. The output should be printed in sorted order.
Examples :
Input : arr1[] = {10, 20, 30} arr2[] = {20, 25, 30, 40, 50} Output : 10 25 40 50 We do not print 20 and 30 as these elements are present in both arrays. Input : arr1[] = {10, 20, 30} arr2[] = {40, 50} Output : 10 20 30 40 50
The idea is based on merge process of merge sort. We traverse both arrays and skip common elements.
Javascript
<script> // JavaScript program to find uncommon elements // of two sorted arrays function printUncommon(arr1, arr2, n1, n2) { let i = 0, j = 0, k = 0; while (i < n1 && j < n2) { // If not common, print smaller if (arr1[i] < arr2[j]) { document.write(arr1[i] + " " ); i++; k++; } else if (arr2[j] < arr1[i]) { document.write(arr2[j] + " " ); k++; j++; } // Skip common element else { i++; j++; } } // printing remaining elements while (i < n1) { document.write(arr1[i] + " " ); i++; k++; } while (j < n2) { document.write(arr2[j] + " " ); j++; k++; } } // Driver Code let arr1 = [ 10, 20, 30 ]; let arr2 = [ 20, 25, 30, 40, 50 ]; let n1 = arr1.length; let n2 = arr2.length; printUncommon(arr1, arr2, n1, n2); // This code is contributed by susmitakundugoaldanga. </script> |
10 25 40 50
Time Complexity: O(n1 + n2), where n1 and n2 represents the size of the given two arrays.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please refer complete article on Print uncommon elements from two sorted arrays for more details!
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