String is a sequence of characters. In Java, objects of String are immutable which means they are constant and cannot be changed once created.
Below are 5 ways to compare two Strings in Java:
- Using user-defined function : Define a function to compare values with following conditions :
- if (string1 > string2) it returns a positive value.
- if both the strings are equal lexicographically
i.e.(string1 == string2) it returns 0. - if (string1 < string2) it returns a negative value.
The value is calculated as (int)str1.charAt(i) – (int)str2.charAt(i)
Examples:
Input 1: Lazyroar Input 2: Practice Output: -9 Input 1: Geeks Input 2: Geeks Output: 0 Input 1: Lazyroar Input 2: Geeks Output: 8
Program:
// Java program to Compare two strings
// lexicographically
public
class
GFG {
// This method compares two strings
// lexicographically without using
// library functions
public
static
int
stringCompare(String str1, String str2)
{
int
l1 = str1.length();
int
l2 = str2.length();
int
lmin = Math.min(l1, l2);
for
(
int
i =
0
; i < lmin; i++) {
int
str1_ch = (
int
)str1.charAt(i);
int
str2_ch = (
int
)str2.charAt(i);
if
(str1_ch != str2_ch) {
return
str1_ch - str2_ch;
}
}
// Edge case for strings like
// String 1="Geeks" and String 2="Geeksforgeeks"
if
(l1 != l2) {
return
l1 - l2;
}
// If none of the above conditions is true,
// it implies both the strings are equal
else
{
return
0
;
}
}
// Driver function to test the above program
public
static
void
main(String args[])
{
String string1 =
new
String(
"Geeksforgeeks"
);
String string2 =
new
String(
"Practice"
);
String string3 =
new
String(
"Geeks"
);
String string4 =
new
String(
"Geeks"
);
// Comparing for String 1 < String 2
System.out.println(
"Comparing "
+ string1 +
" and "
+ string2
+
" : "
+ stringCompare(string1, string2));
// Comparing for String 3 = String 4
System.out.println(
"Comparing "
+ string3 +
" and "
+ string4
+
" : "
+ stringCompare(string3, string4));
// Comparing for String 1 > String 4
System.out.println(
"Comparing "
+ string1 +
" and "
+ string4
+
" : "
+ stringCompare(string1, string4));
}
}
Output:Comparing Geeksforgeeks and Practice : -9 Comparing Geeks and Geeks : 0 Comparing Geeksforgeeks and Geeks : 8
- Using String.equals() :In Java, string equals() method compares the two given strings based on the data/content of the string. If all the contents of both the strings are same then it returns true. If any character does not match, then it returns false.
Syntax:
str1.equals(str2);
Here str1 and str2 both are the strings which are to be compared.
Examples:
Input 1: Lazyroar Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: geeks Input 2: Geeks Output: false
Program:
// Java program to Compare two strings
// lexicographically
public
class
GFG {
public
static
void
main(String args[])
{
String string1 =
new
String(
"Geeksforgeeks"
);
String string2 =
new
String(
"Practice"
);
String string3 =
new
String(
"Geeks"
);
String string4 =
new
String(
"Geeks"
);
String string5 =
new
String(
"geeks"
);
// Comparing for String 1 != String 2
System.out.println(
"Comparing "
+ string1 +
" and "
+ string2
+
" : "
+ string1.equals(string2));
// Comparing for String 3 = String 4
System.out.println(
"Comparing "
+ string3 +
" and "
+ string4
+
" : "
+ string3.equals(string4));
// Comparing for String 4 != String 5
System.out.println(
"Comparing "
+ string4 +
" and "
+ string5
+
" : "
+ string4.equals(string5));
// Comparing for String 1 != String 4
System.out.println(
"Comparing "
+ string1 +
" and "
+ string4
+
" : "
+ string1.equals(string4));
}
}
Output:Comparing Geeksforgeeks and Practice : false Comparing Geeks and Geeks : true Comparing Geeks and geeks : false Comparing Geeksforgeeks and Geeks : false
- Using String.equalsIgnoreCase() : The String.equalsIgnoreCase() method compares two strings irrespective of the case (lower or upper) of the string. This method returns true if the argument is not null and the contents of both the Strings are same ignoring case, else false.
Syntax:
str2.equalsIgnoreCase(str1);
Here str1 and str2 both are the strings which are to be compared.
Examples:
Input 1: Lazyroar Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: geeks Input 2: Geeks Output: true
Program:
// Java program to Compare two strings
// lexicographically
public
class
GFG {
public
static
void
main(String args[])
{
String string1 =
new
String(
"Geeksforgeeks"
);
String string2 =
new
String(
"Practice"
);
String string3 =
new
String(
"Geeks"
);
String string4 =
new
String(
"Geeks"
);
String string5 =
new
String(
"geeks"
);
// Comparing for String 1 != String 2
System.out.println(
"Comparing "
+ string1 +
" and "
+ string2
+
" : "
+ string1.equalsIgnoreCase(string2));
// Comparing for String 3 = String 4
System.out.println(
"Comparing "
+ string3 +
" and "
+ string4
+
" : "
+ string3.equalsIgnoreCase(string4));
// Comparing for String 4 = String 5
System.out.println(
"Comparing "
+ string4 +
" and "
+ string5
+
" : "
+ string4.equalsIgnoreCase(string5));
// Comparing for String 1 != String 4
System.out.println(
"Comparing "
+ string1 +
" and "
+ string4
+
" : "
+ string1.equalsIgnoreCase(string4));
}
}
Output:Comparing Geeksforgeeks and Practice : false Comparing Geeks and Geeks : true Comparing Geeks and geeks : true Comparing Geeksforgeeks and Geeks : false
- Using Objects.equals() : Object.equals(Object a, Object b) method returns true if the arguments are equal to each other and false otherwise. Consequently, if both arguments are null, true is returned and if exactly one argument is null, false is returned. Otherwise, equality is determined by using the equals() method of the first argument.
Syntax:
public static boolean equals(Object a, Object b)
Here a and b both are the string objects which are to be compared.
Examples:
Input 1: Lazyroar Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: null Input 2: null Output: true
Program:
// Java program to Compare two strings
// lexicographically
import
java.util.*;
public
class
GFG {
public
static
void
main(String args[])
{
String string1 =
new
String(
"Geeksforgeeks"
);
String string2 =
new
String(
"Geeks"
);
String string3 =
new
String(
"Geeks"
);
String string4 =
null
;
String string5 =
null
;
// Comparing for String 1 != String 2
System.out.println(
"Comparing "
+ string1 +
" and "
+ string2
+
" : "
+ Objects.equals(string1, string2));
// Comparing for String 2 = String 3
System.out.println(
"Comparing "
+ string2 +
" and "
+ string3
+
" : "
+ Objects.equals(string2, string3));
// Comparing for String 1 != String 4
System.out.println(
"Comparing "
+ string1 +
" and "
+ string4
+
" : "
+ Objects.equals(string1, string4));
// Comparing for String 4 = String 5
System.out.println(
"Comparing "
+ string4 +
" and "
+ string5
+
" : "
+ Objects.equals(string4, string5));
}
}
Output:Comparing Geeksforgeeks and Geeks : false Comparing Geeks and Geeks : true Comparing Geeksforgeeks and null : false Comparing null and null : true
- Using String.compareTo() :
Syntax:
int str1.compareTo(String str2)
Working:
It compares and returns the following values as follows:- if (string1 > string2) it returns a positive value.
- if both the strings are equal lexicographically
i.e.(string1 == string2) it returns 0. - if (string1 < string2) it returns a negative value.
Examples:
Input 1: Lazyroar Input 2: Practice Output: -9 Input 1: Geeks Input 2: Geeks Output: 0 Input 1: Lazyroar Input 2: Geeks Output: 8
Program:
// Java program to Compare two strings
// lexicographically
import
java.util.*;
public
class
GFG {
public
static
void
main(String args[])
{
String string1 =
new
String(
"Geeksforgeeks"
);
String string2 =
new
String(
"Practice"
);
String string3 =
new
String(
"Geeks"
);
String string4 =
new
String(
"Geeks"
);
// Comparing for String 1 < String 2
System.out.println(
"Comparing "
+ string1 +
" and "
+ string2
+
" : "
+ string1.compareTo(string2));
// Comparing for String 3 = String 4
System.out.println(
"Comparing "
+ string3 +
" and "
+ string4
+
" : "
+ string3.compareTo(string4));
// Comparing for String 1 > String 4
System.out.println(
"Comparing "
+ string1 +
" and "
+ string4
+
" : "
+ string1.compareTo(string4));
}
}
Output:Comparing Geeksforgeeks and Practice : -9 Comparing Geeks and Geeks : 0 Comparing Geeksforgeeks and Geeks : 8
Why not to use == for comparison of Strings?
In general both equals() and “==” operator in Java are used to compare objects to check equality but here are some of the differences between the two:
- Main difference between .equals() method and == operator is that one is method and other is operator.
- One can use == operators for reference comparison (address comparison) and .equals() method for content comparison.
- Both s1 and s2 refers to different objects.
- When one uses == operator for s1 and s2 comparison then the result is false as both have different addresses in memory.
- Using equals, the result is true because its only comparing the values given in s1 and s2.
In simple words, == checks if both objects point to the same memory location whereas .equals() evaluates to the comparison of values in the objects.
Example:
// Java program to understand // why to avoid == operator public class Test { public static void main(String[] args) { String s1 = new String( "HELLO" ); String s2 = new String( "HELLO" ); System.out.println(s1 == s2); System.out.println(s1.equals(s2)); } } |
false true
Explanation: Here two String objects are being created namely s1 and s2.