The java.lang.Math.floor() returns the double value that is less than or equal to the argument and is equal to the nearest mathematical integer. Note:
- If the argument is Integer, then the result is Integer.
- If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
public static double floor(double a) a : the argument whose floor value is to be determined Returns : This method returns the double value that is less than or equal to the argument and is equal to the nearest mathematical integer.
Example 01:To show working of java.lang.Math.floor() method.
java
// Java program to demonstrate working// of java.lang.Math.floor() methodimport java.lang.Math;class Gfg { // Main driver code public static void main(String args[]) { double a = 4.3; double b = 1.0 / 0; double c = 0.0; double d = -0.0; double e = -2.3; System.out.println(Math.floor(a)); // Input Infinity, Output Infinity System.out.println(Math.floor(b)); // Input Positive Zero, Output Positive Zero System.out.println(Math.floor(c)); // Input Negative Zero, Output Negative Zero System.out.println(Math.floor(d)); // Input -2.3, Output -3.0 // Nearest Integer(-3.0) < less than (-2.3) System.out.println(Math.floor(e)); }} |
Output:
4.0 Infinity 0.0 -0.0 -3.0
Example 02:To show the working of floor() with a positive double value.
Java
import java.io.*;class GFG { public static void main(String[] args) { double number = 3.5; // double num-3.5 double result = Math.floor(number); System.out.println(result); // Output: 3.0 }} |
Output :
3.0
