The computeIfPresent(Key, BiFunction) method of Properties class which allows you to compute value of a mapping for specified key if key is already associated with a value (or is mapped to null).
- If mapping function of this method returns null, the mapping is removed.
- If the remapping function throws an exception, the exception is rethrown, and the mapping is left unchanged.
- During computation, modification this map using this method is not allowed.
- This method will throw a ConcurrentModificationException if the remapping function modified this map during computation.
Syntax:
public Object computeIfPresent?(Object key, BiFunction remappingFunction)
Parameters: This method accepts two parameters:
- key: key with which the value is to be associated.
- remappingFunction: function to do the operation on value.
Returns: This method returns new remapped value associated with the specified key, or null if mapping returns null.
Exception: This method throws ConcurrentModificationException if it is detected that the remapping function modified this map.
Below programs illustrate the computeIfPresent(Key, BiFunction) method:
Program 1:
// Java program to demonstrate // computeIfPresent(Key, BiFunction) method. import java.util.*; public class GFG { // Main method public static void main(String[] args) { // Create a properties and add some values Properties properties = new Properties(); properties.put( "Pen" , 10 ); properties.put( "Book" , 500 ); properties.put( "Clothes" , 400 ); properties.put( "Mobile" , 5000 ); // print Properties details System.out.println( "Current Properties: " + properties.toString()); // provide new value for keys which is present // using computeIfPresent method properties.computeIfPresent( "Pen" , (key, val) -> 600 ); properties.computeIfPresent( "Book" , (key, val) -> 800 ); // print new mapping System.out.println( "New Properties: " + properties.toString()); } } |
Current Properties: {Book=500, Mobile=5000, Pen=10, Clothes=400} New Properties: {Book=800, Mobile=5000, Pen=600, Clothes=400}
Program 2:
// Java program to demonstrate // computeIfPresent(Key, BiFunction) method. import java.util.*; public class GFG { // Main method public static void main(String[] args) { // Create a properties and add some values Properties properties = new Properties(); properties.put( 1 , "100RS" ); properties.put( 2 , "500RS" ); properties.put( 3 , "1000RS" ); // print Properties details System.out.println( "Current Properties: " + properties.toString()); // provide new value for key which is present // using computeIfPresent method properties.computeIfPresent( 3 , (key, val) -> "00RS" ); // this will not effect anything // because key 4 is absent properties.computeIfPresent( 4 , (key, val) -> "$" ); // print new mapping System.out.println( "New Properties: " + properties.toString()); } } |
Current Properties: {3=1000RS, 2=500RS, 1=100RS} New Properties: {3=00RS, 2=500RS, 1=100RS}