Given a square matrix of order n*n, you have to interchange the elements of both diagonals.
Examples :
Input : matrix[][] = {1, 2, 3, 4, 5, 6, 7, 8, 9} Output : matrix[][] = {3, 2, 1, 4, 5, 6, 9, 8, 7} Input : matrix[][] = {4, 2, 3, 1, 5, 7, 6, 8, 9, 11, 10, 12, 16, 14, 15, 13} Output : matrix[][] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 11, 14, 15, 16}
Explanation : Idea behind interchanging diagonals of a square matrix is simple. Iterate from 0 to n-1 and for each iteration you have to swap a[i][i] and a[i][n-i-1].
Java
// Java program to interchange // the diagonals of matrix import java.io.*; class GFG { public static int N = 3 ; // Function to interchange diagonals static void interchangeDiagonals( int array[][]) { // swap elements of diagonal for ( int i = 0 ; i < N; ++i) if (i != N / 2 ) { int temp = array[i][i]; array[i][i] = array[i][N - i - 1 ]; array[i][N - i - 1 ] = temp; } for ( int i = 0 ; i < N; ++i) { for ( int j = 0 ; j < N; ++j) System.out.print(array[i][j]+ " " ); System.out.println(); } } // Driver Code public static void main (String[] args) { int array[][] = { { 4 , 5 , 6 }, { 1 , 2 , 3 }, { 7 , 8 , 9 } }; interchangeDiagonals(array); } } // This code is contributed by Pramod Kumar |
Output:
6 5 4 1 2 3 9 8 7
Time Complexity: O(N) where N is no of rows or columns; as we are using a single loop for interchanging diagonals of a given matrix.
Auxiliary Space: O(1), as we are not using any extra space.
Please refer complete article on Program to Interchange Diagonals of Matrix for more details!