Given two strings S and N of the same length, consisting of alphabetical and numeric characters respectively, the task is to generate a new string obtained by adding the integer value of each character of string N with the ASCII value of the same indexed character of string S. Finally, print the resultant string.
Note: If the sum exceeds 122, then subtract 26 from the sum and print the resultant character.
Examples:
Input: S = “sun”, N = “966”
Output: “bat”
Explanation:
ASCII value of ‘s’ = 115.
Therefore, 115 + 9 = 124 – 26 = 98. Therefore, equivalent character is’b’.
ASCII value of ‘u’ = 117.
Therefore, 117 + 6 = 123 – 26 = 97. Therefore, equivalent character is ‘a’.
ASCII value of ‘n’ = 110.
Therefore, 110 + 6 = 116. Therefore, equivalent character is ‘t’.Input: S = “apple”, N = “12580”
Output: “brute”
Approach: Follow the steps below to solve the problem:
- Traverse the string S:
- Convert the current character of string N to its equivalent integer value.
- Add the obtained integer value to the equivalent ASCII value of the current character in string S.
- If the value exceeds 122, which is the ASCII value of the last alphabet ‘z’, then subtract the value by 26.
- Update string S by replacing a current character with the character whose ASCII value is equal to the value obtained.
- Print the resultant string after completing the above steps.
Below is the implementation of the above approach:
C++
// C++ program for the above approach #include <bits/stdc++.h> using namespace std; // Function to modify a given string // by adding ASCII value of characters // from a string S to integer values of // same indexed characters in string N void addASCII(string S, string N) { // Traverse the string for ( int i = 0; i < S.size(); i++) { // Stores integer value of // character in string N int a = int (N[i]) - '0' ; // Stores ASCII value of // character in string S int b = int (S[i]) + a; // If b exceeds 122 if (b > 122) b -= 26; // Replace the character S[i] = char (b); } // Print resultant string cout << S; } // Driver Code int main() { // Given strings string S = "sun" , N = "966" ; // Function call to modify // string S by given operations addASCII(S, N); return 0; } |
Java
// Java program for the above approach import java.util.*; class GFG { // Function to modify a given String // by adding ASCII value of characters // from a String S to integer values of // same indexed characters in String N static void addASCII( char []S, char []N) { // Traverse the String for ( int i = 0 ; i < S.length; i++) { // Stores integer value of // character in String N int a = ( int )(N[i]) - '0' ; // Stores ASCII value of // character in String S int b = ( int )(S[i]) + a; // If b exceeds 122 if (b > 122 ) b -= 26 ; // Replace the character S[i] = ( char )(b); } // Print resultant String System.out.print(S); } // Driver Code public static void main(String[] args) { // Given Strings String S = "sun" , N = "966" ; // Function call to modify // String S by given operations addASCII(S.toCharArray(), N.toCharArray()); } } // This code is contributed by shikhasingrajput. |
Python3
# python 3 program for the above approach # Function to modify a given string # by adding ASCII value of characters # from a string S to integer values of # same indexed characters in string N def addASCII(S, N): # Traverse the string for i in range ( len (S)): # Stores integer value of # character in string N a = ord (N[i]) - ord ( '0' ) # Stores ASCII value of # character in string S b = ord (S[i]) + a # If b exceeds 122 if (b > 122 ): b - = 26 # Replace the character S = S.replace(S[i], chr (b)) # Print resultant string print (S) # Driver Code if __name__ = = "__main__" : # Given strings S = "sun" N = "966" # Function call to modify # string S by given operations addASCII(S, N) # This code is contributed by ukasp. |
C#
// C# program for the above approach using System; public class GFG { // Function to modify a given String // by adding ASCII value of characters // from a String S to integer values of // same indexed characters in String N static void addASCII( char []S, char []N) { // Traverse the String for ( int i = 0; i < S.Length; i++) { // Stores integer value of // character in String N int a = ( int )(N[i]) - '0' ; // Stores ASCII value of // character in String S int b = ( int )(S[i]) + a; // If b exceeds 122 if (b > 122) b -= 26; // Replace the character S[i] = ( char )(b); } // Print resultant String Console.Write(S); } // Driver Code public static void Main(String[] args) { // Given Strings String S = "sun" , N = "966" ; // Function call to modify // String S by given operations addASCII(S.ToCharArray(), N.ToCharArray()); } } // This code is contributed by shikhasingrajput |
Javascript
<script> // JavaScript program for the above approach // Function to modify a given string // by adding ASCII value of characters // from a string S to integer values of // same indexed characters in string N function addASCII(S, N) { var newStr = new Array(S.length); // Traverse the string for ( var i = 0; i < S.length; i++) { // Stores integer value of // character in string N var a = N[i].charCodeAt(0) - "0" .charCodeAt(0); // Stores ASCII value of // character in string S var b = S[i].charCodeAt(0) + a; // If b exceeds 122 if (b > 122) b -= 26; // Replace the character newStr[i] = String.fromCharCode(b); } // Print resultant string document.write(newStr.join( "" )); } // Driver Code // Given strings var S = "sun" , N = "966" ; // Function call to modify // string S by given operations addASCII(S, N); </script> |
bat
Time Complexity: O(|S|)
Auxiliary Space: O(1)
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