Given an array of strings Files[], representing name of some files, the task is to sort the array based on the lexicographical order of the extensions of the file names. If more than one files have the same extension, then sort them in lexicographically.
Examples:
Input: files[] = {“ajay.cpp”, “pchy.pdf”, “loki.docx”, “raju.zip” }
Output: ajay.cpp, loki.docx, pchy.pdf, raju.zip
Explanation:
Lexicographically sorted order of “cpp” < “docx” < “pdf” < “zip”Input: files[] = {“abc.cpp”, “bcd.cpp”, “ab.cpp”, “efg.zip”}
Output: ab.cpp, abc.cpp, bcd.cpp, efg.zip
Explanation:
Since the file names { “abc.cpp”, “bcd.cpp”, “ab.cpp” } have same extension, they are sorted lexicographical order of their names.
Approach: Follow the steps below to solve the problem:
- Sort the array of strings based on the extensions using a comparator function.
- For any pair of files with same extension, sort them in lexicographical order of their names.
- Finally, print the array of strings.
Below is the implementation of the above approach:
C++
// C++ Program for the above approach#include <bits/stdc++.h>using namespace std;// Comparator function to sort an array of strings// based on the extension of their file namesbool custom(string s1, string s2){ // Stores index of '.' in s1 size_t i = s1.find('.'); // Stores index of '.' in s2 size_t j = s2.find('.'); // Stores name of extension of s2 string d = s1.substr(i + 1); // Stores name of extension of s2 string e = s2.substr(j + 1); // If both files have the // same extension name if (d == e) { // Return lexicographically // smaller of the two strings return s1 < s2; } return d < e;}// Function to sort the files names// based on the name of their extensionvoid sortfromextension(vector<string>& files){ // Sort file names in lexicographical // order of their extensions sort(files.begin(), files.end(), custom); // Print files in sorted form // based on extension names for (auto s : files) { cout << s << ", "; }}// Driver Codeint main(){ vector<string> files = { "ajay.cpp", "pchy.pdf", "loki.docx", "raju.zip" }; sortfromextension(files); return 0;} |
Java
// Java program for above approachimport java.util.*;import java.lang.*;class GFG{ // Function to sort the files names // based on the name of their extension static void sortfromextension(String[] files) { // Sort file names in lexicographical // order of their extensions Arrays.sort(files, new Comparator<String>(){ public int compare(String s1,String s2){ // Stores index of '.' in s1 int i = s1.indexOf('.'); // Stores index of '.' in s2 int j = s2.indexOf('.'); // Stores name of extension of s2 String d = s1.substring(i + 1); // Stores name of extension of s2 String e = s2.substring(j + 1); return (d.equals(e))?(s1.compareTo(s2)<0?-1:1):(d.compareTo(e)<0?-1:1); } }); // Print files in sorted form // based on extension names for (int i = 0; i < files.length - 1; i++) { System.out.print(files[i] + ", "); } System.out.print(files[files.length - 1]); } // Driver function public static void main (String[] args) { String[] files = { "ajay.cpp", "pchy.pdf", "loki.docx", "raju.zip" }; sortfromextension(files); }}// This code is contributed by offbeat |
C#
using System;using System.Linq;class Program{ // Function to sort the files names // based on the name of their extension static void SortFromExtension(string[] files) { // Sort file names in lexicographical // order of their extensions Array.Sort(files, (s1, s2) => { // Stores index of '.' in s1 int i = s1.IndexOf('.'); // Stores index of '.' in s2 int j = s2.IndexOf('.'); // Stores name of extension of s2 string d = s1.Substring(i + 1); // Stores name of extension of s2 string e = s2.Substring(j + 1); return (d == e) ? string.Compare(s1, s2, StringComparison.Ordinal) : string.Compare(d, e, StringComparison.Ordinal); }); // Print files in sorted form // based on extension names Console.WriteLine(string.Join(", ", files)); } static void Main(string[] args) { string[] files = { "ajay.cpp", "pchy.pdf", "loki.docx", "raju.zip" }; SortFromExtension(files); }} |
Python3
# Pythonimport redef SortFromExtension(files): # Sort file names in lexicographical # order of their extensions files.sort(key=lambda s: re.split("\.([^.]+)", s)[1]) # Print files in sorted form # based on extension names print(", ".join(files))if __name__ == "__main__": files = ["ajay.cpp", "pchy.pdf", "loki.docx", "raju.zip"] SortFromExtension(files)#contributed by akashish__ |
Javascript
// Javascript program for the above approachfunction SortFromExtension(files) { // Sort file names in lexicographical // order of their extensions files.sort(function(a, b) { let ext1 = a.split('.').pop(); let ext2 = b.split('.').pop(); if (ext1 < ext2) { return -1; } else if (ext1 > ext2) { return 1; } else { return a.localeCompare(b); }}); // Print files in sorted form // based on extension names console.log(files.join(', '));}let files = ["ajay.cpp", "pchy.pdf", "loki.docx", "raju.zip"];SortFromExtension(files); // This code is contributed by rishabmalhdjio |
Output
ajay.cpp, loki.docx, pchy.pdf, raju.zip,
Time Complexity: O(N * log(N))
Auxiliary Space: O(1)
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