Given a number N, the task is to find the Nth term of the below series:
23 + 45 + 75 + 113 + 159 +…… upto N terms
Examples:
Input: N = 4
Output: 256
Explanation:
Nth term = (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6
= (2 * 4 * (4 + 1) * (4 * 4 + 17) + 54 * 4) / 6
= 256
Input: N = 10
Output: 2180
Approach:
The Nth term of the given series can be generalized as: 
Sum of first n terms of this series: 
Therefore, Sum of first n terms of this series: 
Below is the implementation of the above approach:
C++
// CPP program to find sum// upto N-th term of the series:// 23, 45, 75, 113...#include <iostream>using namespace std;// calculate Nth term of seriesint findSum(int N){ return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;}// Driver Functionint main(){ // Get the value of N int N = 4; // Get the sum of the series cout << findSum(N) << endl; return 0;} |
Java
// Java program to find sum// upto N-th term of the series:// 23, 45, 75, 113...import java.util.*;class solution { static int findSum(int N){ //return the final sum return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;}//Driver programpublic static void main(String arr[]){// Get the value of N int N = 4;// Get the sum of the series System.out.println(findSum(N));}} |
Python3
# Python3 program to find sum# upto N-th term of the series:# 23, 45, 75, 113...# calculate Nth term of series def findSum(N): return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6 #Driver Functionif __name__=='__main__':#Get the value of N N = 4#Get the sum of the series print(findSum(N))#this code is contributed by Shashank_Sharma |
C#
// C# program to find sum // upto N-th term of the series: // 23, 45, 75, 113... using System; class GFG { static int findSum(int N) { //return the final sum return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6; } // Driver Code static void Main() { // Get the value of N int N = 4; // Get the sum of the series Console.Write(findSum(N)); } } // This code is contributed by Raj |
PHP
<?php// PHP program to find sum// upto N-th term of the series:// 23, 45, 75, 113...// calculate Nth term of seriesfunction findSum($N){ return (2 * $N * ($N + 1) * (4 * $N + 17) + 54 * $N) / 6;}// Driver Code// Get the value of N$N = 4;// Get the sum of the seriesecho findSum($N);// This code is contributed // by anuj_67?> |
Javascript
<script>// javascript program to find sum// upto N-th term of the series:// 23, 45, 75, 113...// calculate Nth term of seriesfunction findSum( N){ return (2 * N * (N + 1) * (4 * N + 17) + 54 * N) / 6;}// Driver Function // Get the value of N let N = 4; // Get the sum of the series document.write(findSum(N)); // This code is contributed by Rajput-Ji </script> |
Output:
256
Time Complexity: O(1)
Auxiliary Space: O(1) since using constant variables
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
