Given a string str, the task is to find the length of the string.
Examples:
Input: str = “Geeks”
Output: Length of Str is : 5Input: str = “neveropen”
Output: Length of Str is: 13
Approach 1: Iterative(using Loop)
The most traditional method of finding the length of the string is by traversing each character through the loop.
- Using a counter, traverse each character of the string with the help of Loop.
- Update the counter for every character
- When the string is terminated or a null character is identified, break the loop.
- Return the counter value as the length of the string.
Below is the implementation of the above method:
C++
// C++ program to find length// of a string#include <bits/stdc++.h>using namespace std;// Driver codeint main(){ // String obj string str = "neveropen"; // The constructor of string will set // it to the C-style string, // which ends at the '\0' // size of string object Using while loop // while 'NOT NULL' int i = 0, cnt = 0; while (str[i]) { i++; cnt++; } cout << cnt << endl; return 0;} |
C
// C program to find the length of string#include <stdio.h>#include <string.h>int main(){ char Str[] = "neveropen"; int i = 0, cnt = 0; while (Str[i]) { cnt++; i++; } printf("%d", cnt); return 0;} |
Java
public class StringLength { public static void main(String[] args) { // String object String str = "neveropen"; // Initialize a variable to count the characters int i = 0, cnt = 0; // Use a while loop to iterate through the characters until the end of the string while (i < str.length()) { i++; cnt++; } // Print the length of the string System.out.println(cnt); }} |
Python3
# Python program to find length# of a string# String objstr = "neveropen"# size of string object Using while loopi = 0cnt = 0while str[i:]: i += 1 cnt += 1print(cnt) |
C#
using System;class Program { static void Main(string[] args) { // String object string str = "neveropen"; // Use the Length property to get the length of the string int length = str.Length; // Print the length of the string Console.WriteLine(length); }} |
Javascript
// String objectlet str = "neveropen";// Initialize a variable to count the characterslet i = 0, cnt = 0;// Use a while loop to iterate through the characters until the end of the stringwhile (str[i] !== undefined) { i++; cnt++;}// Print the length of the stringconsole.log(cnt); |
Output
13
Time Complexity: O(N), where N is the length of the string.
Auxillary space: O(1)
Approach 2: Using In-built methods
Every programming language offers a built-in method as well to find the length of the string, such as:
|
Programming Language |
In-Built method to find the length of the string |
|---|---|
|
C |
strlen() |
|
C++ |
size() |
|
Java |
length() |
|
Python |
len() |
|
Javascript |
length |
|
C# |
length() |
Below is the implementation of the above methods:
C++
// C++ program to find length// of a string#include <iostream>#include <string.h>using namespace std;// Driver codeint main(){ // String obj string str = "neveropen"; // size of string object using size() method cout << str.size() << endl; return 0;} |
C
// C program to find the length of// string using strlen function#include <stdio.h>#include <string.h>int main(){ char Str[] = "neveropen"; printf("%ld", strlen(Str)); return 0;} |
Java
/*package whatever //do not write package name here */import java.io.*;class GFG { public static void main(String[] args) { String str = "neveropen"; int stringSize = str.length(); System.out.println(stringSize); }} |
Python
# Python code to demonstrate string length# using lenstr = "neveropen"print(len(str)) |
C#
using System;class Program{ static void Main() { // String variable string str = "neveropen"; // Length of the string using the Length property Console.WriteLine(str.Length); // Alternatively, you can also use the String.Length method: // Console.WriteLine(str.Length); // Pause the program execution to see the result Console.ReadLine(); }}//Contributed by Aditi Tyagi |
Javascript
// String objectlet str = "neveropen";// Use the `length` property of the string object to get its length// The `length` property directly gives the length of the stringlet length = str.length;// Print the length of the stringconsole.log(length); |
Output
13
Time Complexity: O(1), except strlen() for C it is O(N)
Auxillary Space: O(1)
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