Given a number N. The task is to write a program to find the Nth term of the below series:
0, 7, 18, 33, 51, 75, 102, 133, …(N Terms)
Examples:
Input: N = 4
Output: 33
For N = 4
4th Term = ( 2 * 4 * 4 + 4 - 3)
= 33
Input: N = 10
Output: 206
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// C++ program to find the N-th term of the series:// 0, 7, 18, 33, 51, 75, 102, .....#include <iostream>#include <math.h>using namespace std;// calculate Nth term of seriesint nthTerm(int n){ return 2 * pow(n, 2) + n - 3;}// Driver codeint main(){ int N = 4; cout << nthTerm(N) << endl; return 0;} |
Java
// Java program to find the N-th term of the series:// 0, 7, 18, 33, 51, 75, 102, .....import java.io.*;class GFG { // calculate Nth term of seriesstatic int nthTerm(int n){ return 2 * (int)Math.pow(n, 2) + n - 3;}// Driver code public static void main (String[] args) { int N = 4; System.out.println( nthTerm(N)); }}// This code is contributed // by anuj_67.. |
Python3
# Python3 program to find the # N-th term of the series:# 0, 7, 18, 33, 51, 75, 102, .....# calculate Nth term of seriesdef nthTerm(n): return 2 * pow(n, 2) + n - 3# Driver codeN = 4print(nthTerm(N))# This code is contributed by# Sanjit_Prasad |
C#
// C# program to find the// N-th term of the series:// 0, 7, 18, 33, 51, 75, 102, .....using System;class GFG {// calculate Nth term of seriesstatic int nthTerm(int n){ return 2 * (int)Math.Pow(n, 2) + n - 3;}// Driver codepublic static void Main () { int N = 4; Console.Write( nthTerm(N));}}// This code is contributed // by ChitraNayal |
PHP
<?php// PHP program to find the // N-th term of the series:// 0, 7, 18, 33, 51, 75, 102,...// calculate Nth term of seriesfunction nthTerm($n){ return 2 * pow($n, 2) + $n - 3;}// Driver code$N = 4;echo nthTerm($N) + "\n";// This code is contributed // by Akanksha Rai(Abby_akku)?> |
Javascript
<script>// JavaScript program to find the N-th term of the series:// 0, 7, 18, 33, 51, 75, 102, .....// calculate Nth term of seriesfunction nthTerm( n){ return 2 * Math.pow(n, 2) + n - 3;}// Driver codelet N = 4; document.write( nthTerm(N) );// This code contributed by gauravrajput1 </script> |
Output:
33
Time Complexity: O(1)
Auxiliary Space: O(1) since using constant variables
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