Sunday, January 12, 2025
Google search engine
HomeData Modelling & AIConstruct an Array of size N whose sum of cube of all...

Construct an Array of size N whose sum of cube of all elements is a perfect square

Given an integer N, the tasks is to construct a sorted array arr[] of size N, such that the sum of cube of all elements is a perfect square, i.e. \sum_{}A_i^3=X^2    , where X is an integer.

Examples:  

Input: N = 5 
Output: 1 2 3 4 5 
Explanation 
Sum of cube of all elements = 1 + 8 + 27 + 64 + 125 = 225 
which is a perfect square number.

Input: N = 1 
Output:
 

Solution Approach: 

  1. The sum of cubes of first N natural number is given by:
    (\frac{N \times(N+1)}{2})^2
  2. So, the summation is itself, a perfect square of the integer X^2&=(\frac{N \times(N+1)}{2})^2
  3. Therefore X&=(\frac{N \times(N+1)}{2})    , which is nothing but sum of N natural numbers.
  4. So, just print the first N natural numbers to construct the array.

Below is the implementation of the above approach: 

C++




// C++ implementation of the
// above approach
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to construct an array
// of size N
void constructArray(int N)
{
    for (int i = 1; i <= N; i++) {
 
        // Prints the first N
        // natural numbers
        cout << i << " ";
    }
}
 
// Driver code
int main()
{
    int N = 5;
    constructArray(N);
    return 0;
}


Java




// Java implementation of the
// above approach
import java.io.*;
public class GFG{
     
// Function to construct an array
// of size N
public static void constructArray(int N)
{
    for(int i = 1; i <= N; i++)
    {
        
       // Prints the first N
       // natural numbers
       System.out.print(i + " ");
    }
}
 
// Driver Code
public static void main(String[] args)
{
    int N = 5;
    constructArray(N);
}
}
 
// This code is contributed by divyeshrabadiya07   


Python3




# Python3 implementation of the
# above approach
 
# Function to construct an array
# of size N
def constructArray(N):
     
    for i in range(1, N + 1):
         
        # Prints the first N
        # natural numbers
        print(i, end = ' ')
         
 
# Driver code
if __name__=='__main__':
     
    N = 5
     
    constructArray(N)
 
# This code is contributed by rutvik_56   


C#




// C# implementation of the
// above approach
using System;
class GFG{
     
// Function to construct an array
// of size N
public static void constructArray(int N)
{
    for(int i = 1; i <= N; i++)
    {
         
        // Prints the first N
        // natural numbers
        Console.Write(i + " ");
    }
}
 
// Driver Code
public static void Main(String[] args)
{
    int N = 5;
    constructArray(N);
}
}
 
// This code is contributed by sapnasingh4991


Javascript




<script>
 
// JavaScript implementation of the
// above approach
 
// Function to construct an array
// of size N
function constructArray(N)
{
    for(let i = 1; i <= N; i++)
    {
         
        // Prints the first N
        // natural numbers
        document.write(i + " ");
    }
}
 
// Driver code
let N = 5;
 
constructArray(N);
 
// This code is contributed by Surbhi Tyagi.
 
</script>


Output: 

1 2 3 4 5

 

Time Complexity: O(N) 
Auxiliary Space: O(1)
 

Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!

RELATED ARTICLES

Most Popular

Recent Comments