Given a number N. The task is to write a program to find the Nth term in the below series:
0, 5, 14, 27, 44 …(Nth Term)
Examples:
Input: N = 4
Output: 27
For N = 4,
Nth term = ( 2 * N * N - N - 1 )
= ( 2 * 4 * 4 - 4 - 1 )
= 27
Input: N = 10
Output: 188
Approach: The generalized Nth term of this series:
Nth Term: 2 * N * N - N - 1
Below is the required implementation:
C++
// CPP program to find N-th term of the series:// 0, 5, 14, 27, 44 ...#include <iostream>#include <math.h>using namespace std;// Calculate Nth term of seriesint nthTerm(int n){ return 2 * pow(n, 2) - n - 1;}// Driver codeint main(){ int N = 4; cout << nthTerm(N); return 0;} |
Java
// Java program to find N-th term of the series:// 0, 5, 14, 27, 44 ...import java.util.*;class solution{// Calculate Nth term of seriesstatic int nthTerm(int n){ return 2 *(int)Math.pow(n, 2) - n - 1;}// Driver codepublic static void main(String arr[]){ int N = 4; System.out.println(nthTerm(N));}}//This code is contributed by Surendra_Gangwar |
Python 3
# Python 3 program to find # N-th term of the series:# 0, 5, 14, 27, 44 ...# Calculate Nth term of seriesdef nthTerm(n): return 2 * pow(n, 2) - n - 1# Driver codeif __name__ == "__main__": N = 4 print(nthTerm(N))# This code is contributed # by ChitraNayal |
C#
// C# program to find // N-th term of the series: // 0, 5, 14, 27, 44 ... using System;class GFG { // Calculate Nth term of series static int nthTerm(int n) { return 2 * (int)Math.Pow(n, 2) - n - 1; } // Driver code static public void Main (){ int N = 4; Console.Write(nthTerm(N)); } } // This code is contributed by Raj |
PHP
<?php// PHP program to find // N-th term of the series:// 0, 5, 14, 27, 44 ...// Calculate Nth term of seriesfunction nthTerm($n){ return 2 * pow($n, 2) - $n - 1;}// Driver code$N = 4;echo nthTerm($N);// This code is contributed // by Akanksha Rai(Abby_akku)?> |
Javascript
<script>// JavaScript program to find N-th term of the series:// 0, 5, 14, 27, 44 ...// Calculate Nth term of seriesfunction nthTerm( n){ return 2 * Math.pow(n, 2) - n - 1;}// Driver code let N = 4; document.write( nthTerm(N) );// This code contributed by aashish1995</script> |
Output:
27
Time Complexity: O(1)
Auxiliary Space : O(1) because using constant variables
Note: Sum upto n terms of the above series(Sn) is:
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