Given a number N, the task is to find the Nth term in series 2, 3, 10, 15, 26….
Example:
Input: N = 2
Output: 3
2nd term = (2*2)-1
= 3
Input: N = 5
Output: 26
5th term = (5*5)+1
= 26
Approach:
- Nth number of the series is obtained by
- Squaring the number itself.
- If the number is odd, add 1 to the squared number. And, subtract 1 if the number is even
- Since the starting number of the series is 2
1st term = 2
2nd term = (2 * 2) – 1 = 3
3rd term = (3 * 3) + 1 = 10
4th term = (4 * 4) – 1 = 15
5th term = (5 * 5) + 1 = 26
and so on….
- In general, Nth number is obtained by formula:
Below is the implementation of the above approach:
C++
// C++ program to find Nth term// of the series 2, 3, 10, 15, 26....#include <bits/stdc++.h>using namespace std;// Function to find Nth termint nthTerm(int N){ int nth = 0; // Nth term if (N % 2 == 1) nth = (N * N) + 1; else nth = (N * N) - 1; return nth;}// Driver Methodint main(){ int N = 5; cout << nthTerm(N) << endl; return 0;} |
Java
// Java program to find Nth term// of the series 2, 3, 10, 15, 26....class GFG{// Function to find Nth termstatic int nthTerm(int N){ int nth = 0; // Nth term if (N % 2 == 1) nth = (N * N) + 1; else nth = (N * N) - 1; return nth;}// Driver codepublic static void main(String[] args){ int N = 5; System.out.print(nthTerm(N) +"\n");}}// This code is contributed by Rajput-Ji |
Python3
# Python3 program to find Nth term # of the series 2, 3, 10, 15, 26.... # Function to find Nth term def nthTerm(N) : nth = 0; # Nth term if (N % 2 == 1) : nth = (N * N) + 1; else : nth = (N * N) - 1; return nth; # Driver Method if __name__ == "__main__" : N = 5; print(nthTerm(N)) ; # This code is contributed by AnkitRai01 |
C#
// C# program to find Nth term// of the series 2, 3, 10, 15, 26....using System;class GFG{// Function to find Nth termstatic int nthTerm(int N){ int nth = 0; // Nth term if (N % 2 == 1) nth = (N * N) + 1; else nth = (N * N) - 1; return nth;}// Driver codepublic static void Main(String[] args){ int N = 5; Console.Write(nthTerm(N) +"\n");}}// This code is contributed by PrinciRaj1992 |
Javascript
<script> // Javascript program to find Nth term // of the series 2, 3, 10, 15, 26.... // Function to find Nth term function nthTerm(N) { let nth = 0; // Nth term if (N % 2 == 1) nth = (N * N) + 1; else nth = (N * N) - 1; return nth; } let N = 5; document.write(nthTerm(N)); // This code is contributed by divyeshrabadiya07.</script> |
Output:
26
Time Complexity: O(1) since no loop is used the algorithm takes up constant time to perform the operations
Auxiliary Space: O(1) since no extra array is used so the space taken by the algorithm is constant
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