Given a number N, the task is to find Nth Tetracontaoctagon number.
A Tetracontaoctagon number is a class of figurate numbers. It has a 48-sided polygon called Tetracontaoctagon. The N-th Tetracontaoctagonal number count’s the 48 number of dots and all other dots are surrounding with a common sharing corner and make a pattern. The first few Tetracontaoctagonol numbers are 1, 48, 141, 280, 465, 696, …
Examples:
Input: N = 2
Output: 48
Explanation:
The second Tetracontaoctagonol number is 48.
Input: N = 3
Output: 141
Approach: The N-th Tetracontaoctagonal number is given by the formula:
- Nth term of s sided polygon =
- Therefore Nth term of 48 sided polygon is
Below is the implementation of the above approach:
C++
// C++ implementation for// above approach#include <bits/stdc++.h>using namespace std;// Function to find the // nth Tetracontaoctagonal Numberint TetracontaoctagonalNum(int n){ return (46 * n * n - 44 * n) / 2;}// Driver Codeint main(){ int n = 3; cout << TetracontaoctagonalNum(n); return 0;} |
Java
// Java program for above approachclass GFG{ // Function to find the // nth TetracontaoctagonalNum Numberstatic int TetracontaoctagonalNum(int n) { return (46 * n * n - 44 * n) / 2;} // Driver code public static void main(String[] args) { int n = 3; System.out.print(TetracontaoctagonalNum(n)); } } // This code is contributed by shubham |
Python3
# Python3 Cimplementation for# above approach# Function to find the # nth Tetracontaoctagonal Numberdef TetracontaoctagonalNum(n): return (46 * n * n - 44 * n) / 2;# Driver Coden = 3;print(TetracontaoctagonalNum(n));# This code is contributed by Code_Mech |
C#
// C# program for above approachusing System;class GFG{ // Function to find the // nth TetracontaoctagonalNum Numberstatic int TetracontaoctagonalNum(int n) { return (46 * n * n - 44 * n) / 2;} // Driver code public static void Main() { int n = 3; Console.Write(TetracontaoctagonalNum(n)); } } // This code is contributed by Code_Mech |
Javascript
<script>// Javascript implementation for// above approach// Function to find the // nth Tetracontaoctagonal Numberfunction TetracontaoctagonalNum(n){ return (46 * n * n - 44 * n) / 2;}// Driver Codevar n = 3;document.write(TetracontaoctagonalNum(n));</script> |
Output:
141
Reference: https://en.wikipedia.org/wiki/Tetracontaoctagon
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