Python program to find and count the number of occurrences of 0’s in integers from 1 to N; In this tutorial, you will learn how to find and count integers from 1 to N contain 0’s and 1’s as digits.
How to check if a number contains 0’s digit From 1 to N in python
- Python Program 1: Find the number of integers from 1 to n which contains digits 0’s
- Python Program 2: Find the number of integers from 1 to n which contains digits 0’s
- Python Program 3: Find the number of integers from 1 to n which contains digits 0’s and 1’s
Python Program 1: Find the number of integers from 1 to n which contains digits 0’s
# Python Program to Find the number of integers from 1 to n which contains digits 0's
# input the value of N
n=int(input('Enter the value of n: '))
s=str(n)
z=str(0)
if z in s:
print('Zero is found in {}'.format(n))
else:
print('Zero is not found in {}'.format(n))
Output
Enter the value of n: 10 Zero is found in 10
Python Program 2: Find the number of integers from 1 to n which contains digits 0’s
# Python Program to Find the number of integers from 1 to n which contains digits 0's
# enter the value of N
n=int(input('Enter the value of n: '))
c=0
z=str(0)
for j in range(1,n+1):
if z in str(j):
c+=1
print('{} number has zero as digits up to {}.'.format(c,n))
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Output
Enter the value of n: 50 5 number has zero as digits up to 50.
Python Program 3: Find the number of integers from 1 to n which contains digits 0’s and 1’s
# Python Program to Find the number of integers
# from 1 to n which contains 0's and 1's only
n=int(input('Enter the value of n: '))
def countNumbers(x, n):
# If number is greater than n
if x > n :
return 0
# otherwise add count this number and
# call two functions
return (1 + countNumbers(x * 10, n) +
countNumbers(x * 10 + 1, n))
# Driver code
if __name__ == '__main__':
print('The count is ', countNumbers(1, n));
Output
Enter the value of n: 200 The count is 7
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