Given a string (be it either string of numbers or characters), write a Python program to split the string by every nth character.
Examples:
Input : str = "GeeksforLazyroar", n = 3 Output : ['Gee', 'ksf', 'org', 'eek', 's'] Input : str = "1234567891234567", n = 4 Output : [1234, 5678, 9123, 4567]
Method #1: Using list comprehension
Python3
# Python code to split string# by every 3rd number# String initializationstring = "GeeksforLazyroar"# Defining splitting pointn = 3# Using list comprehensionout = [(string[i:i+n]) for i in range(0, len(string), n)]# Printing outputprint(out) |
Method #2: Using zip_longest
Python3
# Python code to split string of number# and character into every 4th number# Importingfrom itertools import zip_longest# Group function using zip_longest to splitdef group(n, iterable, fillvalue=None): args = [iter(iterable)] * n return zip_longest(fillvalue=fillvalue, *args)# String initializationstr = '123GeeksForGeeks4567'# Split pointn=4# list of separated stringout_string = [''.join(lis) for lis in group(n, str, '')]# Output list initializationout_no = []# Converting list of string into list of integerfor a in out_string: out_no.append(a)# Printing listprint(out_no) |
Output
['123G', 'eeks', 'ForG', 'eeks', '4567']
Method 3: Using a for loop and string slicing.
- Initialize an empty list to store the substrings.
- Define the splitting point, i.e., n=3.
- Create a for loop to iterate over the string.
- In each iteration, append the substring to the list using string slicing.
- Print the output list.
Python3
# Python code to split string# by every 3rd number# String initializationstring = "GeeksforLazyroar"# Defining splitting pointn = 3# Using for loop and string slicingout = []for i in range(0, len(string), n): out.append(string[i:i+n])# Printing outputprint(out) |
Output
['Gee', 'ksf', 'org', 'eek', 's']
Time complexity: O(n), where n is the length of the input string.
Auxiliary space: O(n), as we are storing each substring in a list.
