numpy.setdiff1d() function find the set difference of two arrays and return the unique values in arr1 that are not in arr2.
Syntax : numpy.setdiff1d(arr1, arr2, assume_unique = False)
Parameters :
arr1 : [array_like] Input array.
arr2 : [array_like] Input comparison array.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.Return : [ndarray] 1D array of values in arr1 that are not in arr2. The result is sorted when assume_unique = False, but otherwise only sorted if the input is sorted.
Code #1 :
# Python program explaining # numpy.setdiff1d() function # importing numpy as geek import numpy as geek arr1 = [5, 6, 2, 3, 4] arr2 = [1, 2, 3] gfg = geek.setdiff1d(arr1, arr2) print (gfg) |
Output :
[4 5 6]
Code #2 :
# Python program explaining # numpy.setdiff1d() function # importing numpy as geek import numpy as geek arr1 = [1, 2, 3, 4, 5, 6, 7, 8, 9] arr2 = [1, 3, 5, 7, 9, 11, 13, 15] gfg = geek.setdiff1d(arr1, arr2) print (gfg) |
Output :
[2 4 6 8]
