The numpy.iscomplex() function tests element-wise whether it is a complex number or not(not infinity or not Not a Number) and returns the result as a boolean array. Syntax :
numpy.iscomplex(array)
Parameters :
array : [array_like] Input array whose element we want to test
Return :
boolean array containing the result
Code 1 :
Python
# Python Program illustrating # numpy.iscomplex() method import numpy as geek print ("Is Complex : ", geek.iscomplex([ 1 + 1j , 1 + 0j ]), "\n") print ("Is Complex : ", geek.iscomplex([ 0 + 1j , 0 ]), "\n") |
Output :
Is Complex : [ True False] Is Complex : [ True False]
Code 2 :
Python
# Python Program illustrating # numpy.iscomplex() method import numpy as geek # Returns True/False value for each element a = geek.arange( 20 ).reshape( 5 , 4 ) print ("Is complex : \n", geek.iscomplex(a)) # Returns True/False value as ans # because we have mentioned dtpe in the beginning b = geek.arange( 20 ).reshape( 5 , 4 ).dtype = complex print ("\n",b) print ("\nIs complex : ", geek.iscomplex(b)) b = [[ 1j ], [ 3 ]] print ("\nIs complex : \n", geek.iscomplex(b)) |
Output :
Is complex : [[False False False False] [False False False False] [False False False False] [False False False False] [False False False False]] Is complex : False Is complex : [[ True] [False]]
References : https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.isfinite.html
Note : These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
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