Given a String and a Word, the task is remove that Word from the String.
Examples:
Input: String = “Geeks For Geeks”, Word = “For”
Output: “Geeks Geeks”Input: String = “A computer Science Portal”, Word = “Geeks”
Output: “A computer Science Portal”
Approach : In Java, this can be done using String replaceAll method by replacing given word with a blank space. Below is the solution to the above problem:
C++
// C++ program to remove // a given word from a string #include <bits/stdc++.h> using namespace std; string removeWord(string str, string word) { // Check if the word is present in string // If found, remove it using removeAll() if (str.find(word) != string::npos) { size_t p = -1; // To cover the case // if the word is at the // beginning of the string // or anywhere in the middle string tempWord = word + " " ; while ((p = str.find(word)) != string::npos) str.replace(p, tempWord.length(), "" ); // To cover the edge case // if the word is at the // end of the string tempWord = " " + word; while ((p = str.find(word)) != string::npos) str.replace(p, tempWord.length(), "" ); } // Return the resultant string return str; } // Driver Code int main( int argc, char const * argv[]) { // Test Case 1: // If the word is in the middle string string1 = "Geeks for Geeks." ; string word1 = "for" ; // Test Case 2: // If the word is at the beginning string string2 = "for Geeks Geeks." ; string word2 = "for" ; // Test Case 3: // If the word is at the end string string3 = "Geeks Geeks for." ; string word3 = "for" ; // Test Case 4: // If the word is not present string string4 = "A computer Science Portal." ; string word4 = "Geeks" ; // Test case 1 cout << "String: " << string1 << "\nWord: " << word1 << "\nResult String: " << removeWord(string1, word1) << endl; // Test case 2 cout << "\nString: " << string2 << "\nWord: " << word2 << "\nResult String: " << removeWord(string2, word2) << endl; // Test case 3 cout << "\nString: " << string3 << "\nWord: " << word3 << "\nResult String: " << removeWord(string3, word3) << endl; // Test case 4 cout << "\nString: " << string4 << "\nWord: " << word4 << "\nResult String: " << removeWord(string4, word4) << endl; return 0; } // This code is contributed by // sanjeev2552 |
Java
// Java program to remove // a given word from a string public class GFG { public static String removeWord(String string, String word) { // Check if the word is present in string // If found, remove it using removeAll() if (string.contains(word)) { // To cover the case // if the word is at the // beginning of the string // or anywhere in the middle String tempWord = word + " " ; string = string.replaceAll(tempWord, "" ); // To cover the edge case // if the word is at the // end of the string tempWord = " " + word; string = string.replaceAll(tempWord, "" ); } // Return the resultant string return string; } public static void main(String args[]) { // Test Case 1: // If the word is in the middle String string1 = "Geeks for Geeks." ; String word1 = "for" ; // Test Case 2: // If the word is at the beginning String string2 = "for Geeks Geeks." ; String word2 = "for" ; // Test Case 3: // If the word is at the end String string3 = "Geeks Geeks for." ; String word3 = "for" ; // Test Case 4: // If the word is not present String string4 = "A computer Science Portal." ; String word4 = "Geeks" ; // Test case 1 System.out.println( "String: " + string1 + "\nWord: " + word1 + "\nResult String: " + removeWord(string1, word1)); // Test case 2 System.out.println( "\nString: " + string2 + "\nWord: " + word2 + "\nResult String: " + removeWord(string2, word2)); // Test case 3 System.out.println( "\nString: " + string3 + "\nWord: " + word3 + "\nResult String: " + removeWord(string3, word3)); // Test case 4 System.out.println( "\nString: " + string4 + "\nWord: " + word4 + "\nResult String: " + removeWord(string4, word4)); } } |
C#
// C# program to remove // a given word from a string using System; class GFG { public static String removeWord(String str, String word) { // Check if the word is present in string // If found, remove it using removeAll() if (str.Contains(word)) { // To cover the case // if the word is at the // beginning of the string // or anywhere in the middle String tempWord = word + " " ; str = str.Replace(tempWord, "" ); // To cover the edge case // if the word is at the // end of the string tempWord = " " + word; str = str.Replace(tempWord, "" ); } // Return the resultant string return str; } // Driver code public static void Main(String[] args) { // Test Case 1: // If the word is in the middle String string1 = "Geeks for Geeks." ; String word1 = "for" ; // Test Case 2: // If the word is at the beginning String string2 = "for Geeks Geeks." ; String word2 = "for" ; // Test Case 3: // If the word is at the end String string3 = "Geeks Geeks for." ; String word3 = "for" ; // Test Case 4: // If the word is not present String string4 = "A computer Science Portal." ; String word4 = "Geeks" ; // Test case 1 Console.WriteLine( "String: " + string1 + "\nWord: " + word1 + "\nResult String: " + removeWord(string1, word1)); // Test case 2 Console.WriteLine( "\nString: " + string2 + "\nWord: " + word2 + "\nResult String: " + removeWord(string2, word2)); // Test case 3 Console.WriteLine( "\nString: " + string3 + "\nWord: " + word3 + "\nResult String: " + removeWord(string3, word3)); // Test case 4 Console.WriteLine( "\nString: " + string4 + "\nWord: " + word4 + "\nResult String: " + removeWord(string4, word4)); } } // This code contributed by Rajput-Ji |
Python3
# Python program to remove a given word from a string. def removeWord(string, word): # Check if the word is present in string if word in string: # To cover the case if the word is at the beginning # of the string or anywhere in the middle tempWord = word + " " string = string.replace(tempWord, "") # To cover the edge case if the word is at the end # of the string tempWord = " " + word string = string.replace(tempWord, "") # Return the resultant string return string # Test Case 1 : # If the word is in the middle string1 = "Geeks for Geeks." word1 = "for" # Test Case 2 : # If the word is at the beginning string2 = "for Geeks Geeks." word2 = "for" # Test Case 3 : # If the word is at the end string3 = "Geeks Geeks for." word3 = "for" # Test Case 4 : # If the word is not present string4 = "A computer Science Portal." word4 = "Geeks" # Test case 1 print ( "String:" , string1, "\nWord:" , word1, "\nResult String:" , removeWord(string1, word1)) # Test case 2 print ( "\nString:" , string2, "\nWord:" , word2, "\nResult String:" , removeWord(string2, word2)) # Test case 3 print ( "\nString:" , string3, "\nWord:" , word3, "\nResult String:" , removeWord(string3, word3)) # Test case 4 print ( "\nString:" , string4, "\nWord:" , word4, "\nResult String:" , removeWord(string4, word4)) # This code is contributed by lokeshmvs21. |
String: Geeks for Geeks. Word: for Result String: Geeks Geeks. String: for Geeks Geeks. Word: for Result String: Geeks Geeks. String: Geeks Geeks for. Word: for Result String: Geeks Geeks String: A computer Science Portal. Word: Geeks Result String: A computer Science Portal.