java.util.Collections.disjoint() method is present in java.util.Collections class. It is used to check whether two specified collections are disjoint or not. More formally, two collections are disjoint if they have no elements in common.
Syntax: public static boolean disjoint(Collection<?> c1, Collection<?> c2) Parameters : c1 - a collection c2 - a collection Returns : true if the two specified collections have no elements in common. Throws: NullPointerException - if either collection is null. NullPointerException - if one collection contains a null element and null is not an eligible element for the other collection. ClassCastException - if one collection contains an element that is of a type which is ineligible for the other collection.
Note that it is permissible to pass the same collection in both parameters, in which case the method will return true if and only if the collection is empty.
// Java program to demonstrate working of // java.utils.Collections.disjoint() import java.util.*; public class DisjointDemo{ public static void main(String[] args) { // Let us create array list of strings List<String> mylist1 = new ArrayList<String>(); mylist1.add("practice"); mylist1.add("code"); mylist1.add("quiz"); mylist1.add("neveropen"); // Let us create vector of strings List<String> mylist2 = new Vector<String>(); mylist2.add("geeks"); mylist2.add("geek"); mylist2.add("for"); mylist2.add("coder"); // Let us create a vector List mylist3 = new Vector(); mylist3.add(1); mylist3.add("practice"); // Let us create a Set of strings Set<String> mylist4 = new HashSet<String>(); mylist4.add("practice"); mylist4.add("code"); mylist4.add("quiz"); mylist4.add("neveropen"); // Here we are using disjoint() method to check // whether two collections are disjoint or not System.out.println("is mylist1 disjoint to mylist2 : " + Collections.disjoint(mylist1, mylist2)); System.out.println("is mylist1 disjoint to mylist3 : " + Collections.disjoint(mylist1, mylist3)); System.out.println("is mylist1 disjoint to mylist4 : " + Collections.disjoint(mylist1, mylist4)); }} |
Output:
is mylist1 disjoint to mylist2 : true is mylist1 disjoint to mylist3 : false is mylist1 disjoint to mylist4 : false
How to quickly check whether two arrays in Java are disjoint or not?
Arrays class in Java doesn’t have disjoint method. We can use Collections.disjoint() to check quickly disjoincy of two arrays.
// Java program to demonstrate disjoint // method with arrays import java.util.*; public class DisjointDemo{ public static void main(String[] args) { // Let us create arrays of integers Integer arr1[] = {10, 20, 30, 40, 50}; Integer arr2[] = {60, 70, 80, 90, 100}; Integer arr3[] = {50, 70, 80, 90, 100}; Double arr4[] = {50.0, 60.0, 110.0}; // Please refer below post for details of asList() // Here we are using disjoint() method to check // whether two arrays are disjoint or not System.out.println("is arr1 disjoint to arr2 : " + Collections.disjoint(Arrays.asList(arr1), Arrays.asList(arr2))); System.out.println("is arr1 disjoint to arr3 : " + Collections.disjoint(Arrays.asList(arr1), Arrays.asList(arr3))); System.out.println("is arr1 disjoint to arr4 : " + Collections.disjoint(Arrays.asList(arr1), Arrays.asList(arr4))); }} |
Output:
is arr1 disjoint to arr2 : true is arr1 disjoint to arr3 : false is arr1 disjoint to arr4 : true
This article is contributed by Gaurav Miglani. If you like Lazyroar and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the Lazyroar main page and help other Geeks.
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