AbstractSequentialList listIterator(): method in Java is used to get a listIterator over this list. It returns a list iterator over the elements in this list (in proper sequence).
Syntax:
public abstract ListIterator listIterator(int index)
Parameters: This method takes a parameter index which is the index of first element to be returned from the list iterator (by a call to the next method)
Returns: This method returns a list iterator over the elements in this list (in proper sequence).
Exceptions: This method throws IndexOutOfBoundsException, if the index is out of range (index size())
Below is the code to illustrate ListIterator():
Program 1:
// Java program to demonstrate// add() method import java.util.*; public class GfG { public static void main(String[] args) { // Creating an instance of the AbstractSequentialList AbstractSequentialList<Integer> absl = new LinkedList<>(); // adding elements to absl absl.add(5); absl.add(6); absl.add(7); absl.add(2, 8); absl.add(2, 7); absl.add(1, 9); absl.add(4, 10); // Getting ListIterator ListIterator<Integer> Itr = absl.listIterator(2); // Traversing elements while (Itr.hasNext()) { System.out.print(Itr.next() + " "); } }} |
Output:
6 7 10 8 7
Program 2: To demonstrate IndexOutOfBoundException
// Java code to show IndexOutofBoundException import java.util.*; public class GfG { public static void main(String[] args) { // Creating an instance of the AbstractSequentialList AbstractSequentialList<Integer> absl = new LinkedList<>(); // adding elements to absl absl.add(5); absl.add(6); absl.add(7); absl.add(2, 8); absl.add(2, 7); absl.add(1, 9); absl.add(4, 10); // Printing the list System.out.println(absl); try { // showing IndexOutOfBoundsException // Getting ListIterator ListIterator<Integer> Itr = absl.listIterator(15); // Traversing elements while (Itr.hasNext()) { System.out.print(Itr.next() + " "); } } catch (Exception e) { System.out.println("Exception: " + e); } }} |
Output:
[5, 9, 6, 7, 10, 8, 7] Exception: java.lang.IndexOutOfBoundsException: Index: 15, Size: 7
