Given the total number of Rupees in a bag and the ratio of coins. The bag contains only 1 Rs, 50 paise, 25 paise coins in X, Y, Z, ratio. The task is to determine the number of 1 Rs coins, 50 Paise coins, and 25 paise coins So that after summation of all these we again get the total rupees given.
Examples:
Input: totalRupees = 1800, X = 1, Y = 2, Z = 4
Output: 1 rupees coins = 600
50 paisa coins = 1200
25 paisa coins = 2400
Input: totalRupees = 2500, X = 2, Y = 4, Z = 2
Output: 1 rupees coins = 555
50 paisa coins = 1110
25 paisa coins = 2220
Approach:
Let the ratio in which 1 Rs, 50 paise and 25 paise coin is divided is 1:2:4
Now,
1 Rs coins in a bag is 1x.
50 paise coins in a bag is 2x.
25 paise coins in a bag is 4x.
Now convert these paise into Rupees.
So,
x coins of 1 Rs each, the total value is x rupees.
2x coins of 50 paise i.e (1 / 2) rupees each, the total value is x rupees.
4x coins of 25 paise i.e (1 / 4) rupees each, the total is x rupees.
Therefore,
3x = 1800
x = 600
1 rupee coins = 600 * 1 = 600
50 paisa coins = 600 * 2 = 1200
25 paisa coins = 600 * 4 = 2400
Below is the implementation of the above approach:
C++
// C++ implementation of above approach#include <bits/stdc++.h>using namespace std;// function to calculate coin.int coin(int totalRupees, int X, int Y, int Z){ float one = 0, fifty = 0, twentyfive = 0, result = 0, total = 0; // Converting each of them in rupees. // As we are given totalRupees = 1800 one = X * 1; fifty = ((Y * 1) / 2.0); twentyfive = ((Z * 1) / 4.0); total = one + fifty + twentyfive; result = ((totalRupees) / total); return result;}// Driver codeint main(){ int totalRupees = 1800; int X = 1, Y = 2, Z = 4; int Rupees = coin(totalRupees, X, Y, Z); cout << "1 rupee coins = " << Rupees * 1 << endl; cout << "50 paisa coins = " << Rupees * 2 << endl; cout << "25 paisa coins = " << Rupees * 4 << endl; return 0;} |
Java
// Java implementation of above approach import java.io.*;class GFG { // function to calculate coin. static int coin(int totalRupees, int X, int Y, int Z) { float one = 0, fifty = 0, twentyfive = 0, result = 0, total = 0; // Converting each of them in rupees. // As we are given totalRupees = 1800 one = X * 1; fifty = ((Y * 1) / 2); twentyfive = ((Z * 1) / 4); total = one + fifty + twentyfive; result = ((totalRupees) / total); return (int)result; } // Driver code public static void main (String[] args) { int totalRupees = 1800; int X = 1, Y = 2, Z = 4; int Rupees = coin(totalRupees, X, Y, Z); System.out.println( "1 rupee coins = " + Rupees * 1); System.out.println( "50 paisa coins = " + Rupees * 2); System.out.println( "25 paisa coins = " + Rupees * 4); }}//This code is contributed by inder_verma. |
Python3
# Python3 implementation of above approach# function to calculate coin.def coin(totalRupees, X, Y, Z): # Converting each of them in rupees. # As we are given totalRupees = 1800 one = X * 1 fifty = ((Y * 1) / 2.0) twentyfive = ((Z * 1) / 4.0) total = one + fifty + twentyfive result = ((totalRupees) / total) return int(result)# Driver codeif __name__=='__main__': totalRupees = 1800 X, Y, Z = 1, 2, 4 Rupees = coin(totalRupees, X, Y, Z) print("1 rupee coins = ", Rupees * 1) print("50 paisa coins = ", Rupees * 2) print("25 paisa coins = ", Rupees * 4)# This code is contributed by# Sanjit_Prasad |
C#
// C# implementation of above approach using System;class GFG {// function to calculate coin. static int coin(int totalRupees, int X, int Y, int Z) { float one = 0, fifty = 0, twentyfive = 0, result = 0, total = 0; // Converting each of them in rupees. // As we are given totalRupees = 1800 one = X * 1; fifty = ((Y * 1) / 2); twentyfive = ((Z * 1) / 4); total = one + fifty + twentyfive; result = ((totalRupees) / total); return (int)result; } // Driver code public static void Main () { int totalRupees = 1800; int X = 1, Y = 2, Z = 4; int Rupees = coin(totalRupees, X, Y, Z); Console.WriteLine( "1 rupee coins = " + Rupees * 1); Console.WriteLine( "50 paisa coins = " + Rupees * 2); Console.WriteLine( "25 paisa coins = " + Rupees * 4); }}// This code is contributed by inder_verma |
PHP
<?php // PHP implementation of above approach//function to calculate coinfunction coin($totalRupees, $X, $Y, $Z) { $one = 0; $fifty = 0; $twentyfive = 0; $result = 0; $total = 0; // Converting each of them in rupees. // As we are given totalRupees = 1800 $one = $X * 1; $fifty = (($Y * 1) / 2.0); $twentyfive = (($Z * 1) / 4.0); $total = $one + $fifty + $twentyfive; $result = (($totalRupees) / $total); return $result; } // Driver Code $totalRupees = 1800;$X = 1; $Y = 2; $Z = 4; $Rupees = coin($totalRupees, $X, $Y, $Z);echo "1 rupee coins = ", $Rupees * 1, "\n";echo "50 paisa coins = ", $Rupees * 2, "\n";echo "25 paisa coins = ", $Rupees * 4, "\n";// This code is contributed // by Shashank_Sharma. ?> |
Javascript
<script>// Javascript implementation of above approach// function to calculate coin.function coin(totalRupees, X, Y, Z){ var one = 0, fifty = 0, twentyfive = 0, result = 0, total = 0; // Converting each of them in rupees. // As we are given totalRupees = 1800 one = X * 1; fifty = ((Y * 1) / 2.0); twentyfive = ((Z * 1) / 4.0); total = one + fifty + twentyfive; result = ((totalRupees) / total); return result;}// Driver codevar totalRupees = 1800;var X = 1, Y = 2, Z = 4;var Rupees = coin(totalRupees, X, Y, Z);document.write( "1 rupee coins = " + Rupees * 1 + "<br>");document.write( "50 paisa coins = " + Rupees * 2 + "<br>");document.write( "25 paisa coins = " + Rupees * 4 + "<br>");</script> |
Output
1 rupee coins = 600 50 paisa coins = 1200 25 paisa coins = 2400
Time Complexity: O(1)
Auxiliary Space: O(1)
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