Given three float values M, H, and V representing the mass, velocity, and height of an object respectively the task is to calculate its Kinetic Energy as well as its Potential Energy,
Note: The value of acceleration due to gravity (g) is 9.8 and ignore units.
Examples:
Input: M = 25, H = 10, V = 15
Output:
Kinetic Energy = 2812.5
Potential Energy = 2450
Explanation : The kinetic energy of the particle is 2812.5 and the potential energy is 2450.Input : M=5.5, H=23.5, V= 10.5
Output :
303.188
1266.65
Approach: The required values of Kinetic Energy and Potential Energy can be calculated using the following two formulas:
Kinetic Energy = 0.5 * Mass ( M ) * Velocity ( V ) 2
Potential Energy = Mass ( M ) * Height ( H ) * Acceleration due to gravity ( g )
Below is the implementation of the above approach:
C++14
// C++ Program to implement// the above approach#include <bits/stdc++.h>using namespace std;// Function to calculate Kinetic Energyfloat kineticEnergy(float M, float V){ // Stores the Kinetic Energy float KineticEnergy; KineticEnergy = 0.5 * M * V * V; return KineticEnergy;}// Function to calculate Potential Energyfloat potentialEnergy(float M, float H){ // Stores the Potential Energy float PotentialEnergy; PotentialEnergy = M * 9.8 * H; return PotentialEnergy;}// Driver Codeint main(){ float M = 5.5, H = 23.5, V = 10.5; cout << "Kinetic Energy = " << kineticEnergy(M, V) << endl; cout << "Potential Energy = " << potentialEnergy(M, H) << endl; return 0;} |
Java
// Java program to implement// the above approachclass GFG{ // Function to calculate Kinetic Energystatic double kineticEnergy(double M, double V){ // Stores the Kinetic Energy double KineticEnergy; KineticEnergy = 0.5 * M * V * V; return KineticEnergy;}// Function to calculate Potential Energystatic double potentialEnergy(double M, double H){ // Stores the Potential Energy double PotentialEnergy; PotentialEnergy = M * 9.8 * H; return PotentialEnergy;}// Driver Codepublic static void main(String []args){ double M = 5.5, H = 23.5, V = 10.5; System.out.println("Kinetic Energy = " + kineticEnergy(M, V)); System.out.println("Potential Energy = " + potentialEnergy(M, H));}}// This code is contributed by AnkThon |
Python3
# Python3 program to implement# the above approach# Function to calculate Kinetic Energydef kineticEnergy(M, V): # Stores the Kinetic Energy KineticEnergy = 0.5 * M * V * V return KineticEnergy# Function to calculate Potential Energydef potentialEnergy(M, H): # Stores the Potential Energy PotentialEnergy = M * 9.8 * H return PotentialEnergy# Driver Codeif __name__ == "__main__": M = 5.5 H = 23.5 V = 10.5 print("Kinetic Energy = ", kineticEnergy(M, V)) print("Potential Energy = ", potentialEnergy(M, H)) # This code is contributed by AnkThon |
C#
// C# program to implement// the above approachusing System;using System.Collections.Generic;class GFG{ /// Function to calculate Kinetic Energystatic double kineticEnergy(double M, double V){ // Stores the Kinetic Energy double KineticEnergy; KineticEnergy = 0.5 * M * V * V; return KineticEnergy;}// Function to calculate Potential Energystatic double potentialEnergy(double M, double H){ // Stores the Potential Energy double PotentialEnergy; PotentialEnergy = M * 9.8 * H; return PotentialEnergy;}// Driver Codepublic static void Main(){ double M = 5.5, H = 23.5, V = 10.5; Console.WriteLine("Kinetic Energy = " + kineticEnergy(M, V)); Console.Write("Potential Energy = " + potentialEnergy(M, H));}}// This code is contributed by bgangwar59 |
Javascript
<script> // Javascript program for the above approach // Function to calculate Kinetic Energy function kineticEnergy(M, V) { // Stores the Kinetic Energy let KineticEnergy; KineticEnergy = 0.5 * M * V * V; return KineticEnergy; } // Function to calculate Potential Energy function potentialEnergy(M, H) { // Stores the Potential Energy let PotentialEnergy; PotentialEnergy = M * 9.8 * H; return PotentialEnergy; } // Driver Code let M = 5.5, H = 23.5, V = 10.5; document.write("Kinetic Energy = " + kineticEnergy(M, V)) document.write("<br>"); document.write( "Potential Energy = " + potentialEnergy(M, H)) // This code is contributed by Hritik </script> |
Output:
Kinetic Energy = 303.188 Potential Energy = 1266.65
Time Complexity: O(1)
Auxiliary Space: O(1)
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