Given a square matrix of order n*n, you have to interchange the elements of both diagonals.
Examples :
Input : matrix[][] = {1, 2, 3,
4, 5, 6,
7, 8, 9}
Output : matrix[][] = {3, 2, 1,
4, 5, 6,
9, 8, 7}
Input : matrix[][] = {4, 2, 3, 1,
5, 7, 6, 8,
9, 11, 10, 12,
16, 14, 15, 13}
Output : matrix[][] = {1, 2, 3, 4,
5, 6, 7, 8,
9, 10, 11, 12,
11, 14, 15, 16}
Explanation : Idea behind interchanging diagonals of a square matrix is simple. Iterate from 0 to n-1 and for each iteration you have to swap a[i][i] and a[i][n-i-1].
Python3
# Python program to interchange # the diagonals of matrixN = 3;# Function to interchange diagonalsdef interchangeDiagonals(array): # swap elements of diagonal for i in range(N): if (i != N / 2): temp = array[i][i]; array[i][i] = array[i][N - i - 1]; array[i][N - i - 1] = temp; for i in range(N): for j in range(N): print(array[i][j], end = " "); print();# Driver Codeif __name__ == '__main__': array = [ 4, 5, 6 ],[ 1, 2, 3 ],[ 7, 8, 9 ]; interchangeDiagonals(array); # This code is contributed by Rajput-Ji |
Output:
6 5 4 1 2 3 9 8 7
Time Complexity: O(N) where N is no of rows or columns; as we are using single loop for interchanging diagonals of a given matrix.
Auxiliary Space: O(1), as we are not using any extra space.
Please refer complete article on Program to Interchange Diagonals of Matrix for more details!
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