Given a curve [ y = x(A – x) ], the task is to find normal at a given point ( x, y) on that curve, where A is an integer number and x, y also any integer.
Examples:
Input: A = 2, x = 2, y = 0 Output: 2y = x - 2 Since y = x(2 - x) y = 2x - x^2 differentiate it with respect to x dy/dx = 2 - 2x put x = 2, y = 0 in this equation dy/dx = 2 - 2* 2 = -2 equation => (Y - 0 ) = ((-1/-2))*( Y - 2) => 2y = x -2 Input: A = 3, x = 4, y = 5 Output: Not possible Point is not on that curve
Approach: First we need to find given point is on that curve or not if the point is on that curve then:
- We need to differentiate that equation that point don’t think too much for differentiation of this equation if you analyze then you find that dy/dx always become A – 2x.
- Put x, y in dy/dx.
- Equation of normal is Y – y = -(1/( dy/dx )) * (X – x).
Below is the implementation of the above approach:
C++
// C++ program for find curve // at given point #include <bits/stdc++.h> using namespace std; // function for find normal void findNormal( int A, int x, int y) { // differentiate given equation int dif = A - x * 2; // check that point on the curve or not if (y == (2 * x - x * x)) { // if differentiate is negative if (dif < 0) cout << 0 - dif << "y = " << "x" << (0 - x) + (y * dif); else if (dif > 0) // differentiate is positive cout << dif << "y = " << "-x+" << x + dif * y; // differentiate is zero else cout << "x = " << x; } // other wise normal not found else cout << "Not possible" ; } // Driver code int main() { // declare variable int A = 2, x = 2, y = 0; // call function findNormal findNormal(A, x, y); return 0; } |
Java
// Java program for find curve // at given point import java.io.*; class GFG { // function for find normal static void findNormal( int A, int x, int y) { // differentiate given equation int dif = A - x * 2 ; // check that point on the curve or not if (y == ( 2 * x - x * x)) { // if differentiate is negative if (dif < 0 ) System.out.print( ( 0 - dif) + "y = " + "x" +(( 0 - x) + (y * dif))); else if (dif > 0 ) // differentiate is positive System.out.print( dif + "y = " + "-x+" + (x + dif * y)); // differentiate is zero else System.out.print( "x = " +x); } // other wise normal not found else System.out.println( "Not possible" ); } // Driver code public static void main (String[] args) { // declare variable int A = 2 , x = 2 , y = 0 ; // call function findNormal findNormal(A, x, y);; } } // This Code is contributed by inder_verma.. |
Python3
# Python 3 program for find curve # at given point # function for find normal def findNormal(A, x, y): # differentiate given equation dif = A - x * 2 # check that point on the curve or not if (y = = ( 2 * x - x * x)): # if differentiate is negative if (dif < 0 ): print ( 0 - dif, "y =" , "x" , ( 0 - x) + (y * dif)) elif (dif > 0 ): # differentiate is positive print (dif, "y =" , "- x +" , x + dif * y) # differentiate is zero else : print ( "x =" , x) # other wise normal not found else : print ( "Not possible" ) # Driver code if __name__ = = '__main__' : # declare variable A = 2 x = 2 y = 0 # call function findNormal findNormal(A, x, y) # This code is contributed By # Surendra_Gangwar |
C#
// C# program for find curve // at given point using System; class GFG { // function for find normal static void findNormal( int A, int x, int y) { // differentiate given equation int dif = A - x * 2; // check that point on // the curve or not if (y == (2 * x - x * x)) { // if differentiate is negative if (dif < 0) Console.Write((0 - dif) + "y = " + "x" + ((0 - x) + (y * dif))); else if (dif > 0) // differentiate is positive Console.Write(dif + "y = " + "-x + " + (x + dif * y)); // differentiate is zero else Console.Write( "x = " + x); } // other wise normal not found else Console.WriteLine( "Not possible" ); } // Driver code static public void Main () { // declare variable int A = 2, x = 2, y = 0; // call function findNormal findNormal(A, x, y); } } // This code is contributed by ajit |
PHP
<?php // PHP program for find curve // at given point // function for find normal function findNormal( $A , $x , $y ) { // differentiate given equation $dif = $A - $x * 2; // check that point on the // curve or not if ( $y == (2 * $x - $x * $x )) { // if differentiate is negative if ( $dif < 0) echo (0 - $dif ), "y = " , "x" , (0 - $x ) + ( $y * $dif ); else if ( $dif > 0) // differentiate is positive echo $dif , "y = " , "-x+" ,( $x + $dif * $y ); // differentiate is zero else echo "x = " , $x ; } // other wise normal not found else echo "Not possible" ; } // Driver code // declare variable $A = 2; $x = 2; $y = 0; // call function findNormal findNormal( $A , $x , $y ); // This code is contributed by ajit ?> |
Javascript
<script> // Javascript program for find curve at given point // function for find normal function findNormal(A, x, y) { // differentiate given equation let dif = A - x * 2; // check that point on // the curve or not if (y == (2 * x - x * x)) { // if differentiate is negative if (dif < 0) document.write((0 - dif) + "y = " + "x" + ((0 - x) + (y * dif))); else if (dif > 0) // differentiate is positive document.write(dif + "y = " + "-x + " + (x + dif * y)); // differentiate is zero else document.write( "x = " + x); } // other wise normal not found else document.write( "Not possible" ); } // declare variable let A = 2, x = 2, y = 0; // call function findNormal findNormal(A, x, y); </script> |
2y = x-2
Time Complexity : O(1) ,as we are not using any loop.
Auxiliary Space : O(1) ,as we are not using any extra space.
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