Given a number, the task is to write a Python program to calculate square of the given number.
Examples:
Input: 4 Output: 16 Input: 3 Output: 9 Input: 10 Output: 100
We will provide the number, and we will get the square of that number as output. We have three ways to do so:
- Multiplying the number to get the square (N * N)
- Using Exponent Operator
- Using math.pow() Method
Method 1: Multiplication
In this approach, we will multiply the number with one another to get the square of the number.
Example:
Python3
# Declaring the number.n = 4# Finding square by multiplying them# with each othersquare = n * n# Printing squareprint(square) |
Output:
16
Method 2: Using Exponent Operator
In this approach, we use the exponent operator to find the square of the number.
Exponent Operator: **
Return: a ** b will return a raised to power b as output.
Example:
Python3
# Declaring the number.n = 4# Finding square by using exponent operator# This will yield n power 2 i.e. square of nsquare = n ** 2# Printing squareprint(square) |
Output:
16
Method 3: Using pow() Method
In this approach, we will use the pow() method to find the square of the number. This function computes x**y and returns a float value as output.
Syntax: float pow(x,y)
Parameters :
x : Number whose power has to be calculated.
y : Value raised to compute power.
Return Value :
Returns the value x**y in float.
Example:
Python3
# Declaring the number.n = 4# Finding square by using pow method# This will yield n power 2 i.e. square of nsquare = pow(n, 2)# Printing squareprint(square) |
Output:
16.0
Method 4 : Using operator.pow() method
Approach
- Declaring number
- Raised each element to power 2 using operator.pow() and assigned to output variable
- Displayed output
Python3
# Declaring the number.n = 4# Finding square by using pow methodimport operatorsquare = operator.pow(n, 2)# Printing squareprint(square) |
16
Time Complexity : O(N)
Auxiliary Space : O(1)
Method to find the square of a number using bitwise operators:
This method uses the bitwise left shift operator (<<) to multiply the number by 2, effectively finding the square of the number.
Python3
# Declaring the number.n = 4# Finding square using bitwise left shift operatorsquare = n << 1# Printing squareprint(square) |
8
Time complexity: O(1)
Auxiliary space: O(1) as it only uses a single variable to store the result.
