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Byte Objects vs String in Python

In Python 2, both str and bytes are the same typeByte objects whereas in Python 3 Byte objects, defined in Python 3 are “sequence of bytes” and similar to “unicode” objects from Python 2. However, there are many differences in strings and Byte objects. Some of them are depicted below: 

 

  • Byte objects are sequence of Bytes, whereas Strings are sequence of characters.
  • Byte objects are in machine readable form internally, Strings are only in human readable form.
  • Since Byte objects are machine readable, they can be directly stored on the disk. Whereas, Strings need encoding before which they can be stored on disk.

 

string vs byte in python

There are methods to convert a byte object to String and String to byte objects.
 

Encoding

PNG, JPEG, MP3, WAV, ASCII, UTF-8 etc are different forms of encodings. An encoding is a format to represent audio, images, text, etc in bytes. Converting Strings to byte objects is termed as encoding. This is necessary so that the text can be stored on disk using mapping using ASCII or UTF-8 encoding techniques.
This task is achieved using encode(). It take encoding technique as argument. Default technique is “UTF-8” technique.
 

Python3




# Python code to demonstrate String encoding
 
# initialising a String
a = 'Lazyroar'
 
# initialising a byte object
c = b'Lazyroar'
 
# using encode() to encode the String
# encoded version of a is stored in d
# using ASCII mapping
d = a.encode('ASCII')
 
# checking if a is converted to bytes or not
if (d==c):
    print ("Encoding successful")
else : print ("Encoding Unsuccessful")


Output: 
 

Encoding successful

 

Decoding

Similarly, Decoding is process to convert a Byte object to String. It is implemented using decode() . A byte string can be decoded back into a character string, if you know which encoding was used to encode it. Encoding and Decoding are inverse processes. 
 

Python3




# Python code to demonstrate Byte Decoding
 
# initialising a String
a = 'Lazyroar'
 
# initialising a byte object
c = b'Lazyroar'
 
# using decode() to decode the Byte object
# decoded version of c is stored in d
# using ASCII mapping
d = c.decode('ASCII')
 
# checking if c is converted to String or not
if (d==a):
    print ("Decoding successful")
else : print ("Decoding Unsuccessful")


Output: 
 

Decoding successful

This article is contributed by Manjeet Singh. If you like Lazyroar and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the Lazyroar main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 

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