Any and All are two built-in functions provided in python used for successive And/Or. Any Returns true if any of the items is True. It returns False if empty or all are false. Any can be thought of as a sequence of OR operations on the provided iterables. It short circuit the execution i.e. stop the execution as soon as the result is known.
Syntax:
any(list of iterables)
Python
# Since all are false, false is returnedprint (any([False, False, False, False]))# Here the method will short-circuit at the# second item (True) and will return True.print (any([False, True, False, False]))# Here the method will short-circuit at the# first (True) and will return True.print (any([True, False, False, False])) |
Output:
False True True
All Returns true if all of the items are True (or if the iterable is empty). All can be thought of as a sequence of AND operations on the provided iterables. It also short circuit the execution i.e. stop the execution as soon as the result is known.
Syntax :
all(list of iterables)
Python
# Here all the iterables are True so all# will return True and the same will be printedprint (all([True, True, True, True]))# Here the method will short-circuit at the# first item (False) and will return False.print (all([False, True, True, False]))# This statement will return False, as no# True is found in the iterablesprint (all([False, False, False])) |
Output :
True False False
Practical Examples
Python
# This code explains how can we# use 'any' function on listlist1 = []list2 = []# Index ranges from 1 to 10 to multiplyfor i in range(1,11): list1.append(4*i)# Index to access the list2 is from 0 to 9for i in range(0,10): list2.append(list1[i]%5==0)print('See whether at least one number is divisible by 5 in list 1=>')print(any(list2)) |
Output:
See whether at least one number is divisible by 5 in list 1=> True
Python
# Illustration of 'all' function in python 3# Take two listslist1=[]list2=[]# All numbers in list1 are in form: 4*i-3for i in range(1,21): list1.append(4*i-3)# list2 stores info of odd numbers in list1for i in range(0,20): list2.append(list1[i]%2==1)print('See whether all numbers in list1 are odd =>')print(all(list2)) |
Output:
See whether all numbers in list1 are odd => True
Truth table:
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