Suppose you are given an array s[1…n] and a procedure reverse (s,i,j) which reverses the order of elements in a between positions i and j (both inclusive). What does the following sequence
do, where 1 < k <= n: reverse (s, 1, k); reverse (s, k + 1, n); reverse (s, 1, n);
(GATE CS 2000)
(A) Rotates s left by k positions
(B) Leaves s unchanged
(C) Reverses all elements of s
(D) None of the above
Answer: (A)
Explanation: Effect of the above 3 reversals for any k is equivalent to left rotation of the array of size n by k. Please see this post for details.
If we rotate an array n times for k = 1 to n, we get the same array back.
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