Given a list, the task is to write a Python program to check if the value exists in the list or not using the lambda function.
Example:
Input : L = [1, 2, 3, 4, 5]
element = 4
Output : Element is Present in the list
Input : L = [1, 2, 3, 4, 5]
element = 8
Output : Element is NOT Present in the list
We can achieve the above functionality using the following two methods.
Method 1: Using Lambda and Count() method
Define a list with integers. Define a lambda function such that it takes array and value as arguments and return the count of value in list.
lambda v:l.count(v)
If the count is zero then print the Element is not present else print element is NOT present.
Python3
arr = [1, 2, 3, 4]v = 3 def x(arr, v): return arr.count(v) if(x(arr, v)): print("Element is Present in the list")else: print("Element is Not Present in the list") |
Output:
Element is Present in the list
Explanation: The arr and v are passed to the lambda function and it evaluates the count of v in the arr and here v = 3 and it is present 1 time in the array and the if condition is satisfied and prints the element Is present in the list.
Method 2: Using Lambda and in keyword
Define a list with integers. Define a lambda function such that it takes array and value as arguments and check if value is present in array using in keyword
lambda v: True if v in l else False
If the lambda return True then print the Element is present else print element is NOT present.
Python3
arr=[1,2,3,4]v=8x=lambda arr,v: True if v in arr else False if(x(arr,v)): print("Element is Present in the list")else: print("Element is Not Present in the list") |
Output:
Element is Not Present in the list
Explanation: The arr and v are passed to the lambda function and it checks if the value is present in an array using IN keyword and here v = 8 and it is NOT Present in the array and returns false so prints the element Is NOT present in the list.
