In this program, we need to accept a tuple and then find the number of times an item is present in the tuple. This can be done in various ways, but in this article, we will see how this can be done using a simple approach and how inbuilt functions can be used to solve this problem.
Examples:
Tuple: (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
Input : 4 Output : 0 times Input : 10 Output : 3 times Input : 8 Output : 4 times
Method 1(Simple Approach):
We keep a counter that keeps on increasing if the required element is found in the tuple.
Python3
# Program to count the number of times an element# Present in the listdef countX(tup, x): count = 0 for ele in tup: if (ele == x): count = count + 1 return count# Driver Codetup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)enq = 4enq1 = 10enq2 = 8print(countX(tup, enq))print(countX(tup, enq1))print(countX(tup, enq2)) |
Output
0 3 4
Method 2(Using count()):
The idea is to use method count() to count number of occurrences.
Python3
# Program to count the number of times an element# Present in the list# Count function is useddef Count(tup, en): return tup.count(en)# Driver Codetup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)enq = 4enq1 = 10enq2 = 8print(Count(tup, enq), "times")print(Count(tup, enq1), "times")print(Count(tup, enq2), "times") |
Output
0 times 3 times 4 times
Method 3: Using list comprehension
Python3
tuple1 = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)x = [i for i in tuple1 if i == 10]print("the element 10 occurs", len(x), "times") |
Output
the element 10 occurs 3 times
Method #4: Using enumerate function
Python3
tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)x=[i for a,i in enumerate(tuple1) if i==10]print("the element 10 occurs",len(x),"times") |
Output
the element 10 occurs 3 times
Method #5: Using lambda function
Python3
tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)x=list(filter(lambda i: (i==10),tuple1))print("the element 10 occurs",len(x),"times") |
Output
the element 10 occurs 3 times
Method #6: Using counter function
Python3
from collections import Countertuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")x=Counter(tuple1)print("the element 10 occurs",x["10"],"times") |
Output
the element 10 occurs 3 times
Method#7: Using Countof function
Python3
tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")import operator as opprint(op.countOf(tuple1,"10")) |
Output
3
