Prerequisite: Dictionaries in Python
A dictionary is a collection which is unordered, changeable, and indexed. In Python, dictionaries are written with curly brackets, and they have keys and values. We can access the values of the dictionary using keys. In this article, 10 different ways of sorting the Python dictionary by values and also reverse sorting by values are discussed.
Using lambda function along with items() and sorted(): The lambda function returns the key(0th element) for a specific item tuple, When these are passed to the sorted() method, it returns a sorted sequence which is then type-casted into a dictionary. keys() method returns a view object that displays a list of all the keys in the dictionary. sorted() is used to sort the keys of the dictionary.
Examples:
Input: my_dict = {2: ‘three’, 1: ‘two’}
Output: [(2, ‘three’), (1, ‘two’)]
Below is the implementation using lambda function:
Python3
# Python program to sort dictionary # by value using lambda function # Initialize a dictionary my_dict = { 2 : 'three' , 1 : 'two' } # Sort the dictionary sorted_dict = sorted ( my_dict.items(), key = lambda kv: kv[ 1 ]) # Print sorted dictionary print ( "Sorted dictionary is :" , sorted_dict) |
Javascript
// Javascript program for the above approach // Initialize a dictionary let my_dict = {2: 'three' , 1: 'two' }; // Sort the dictionary by value using lambda function let sorted_dict = Object.entries(my_dict).sort((a, b) => a[1].localeCompare(b[1])); // Print sorted dictionary console.log( "Sorted dictionary is :" , sorted_dict); // This code is contributed by rishab |
Java
// Java program to sort dictionary by value using lambda function import java.util.*; class Main { public static void main(String[] args) { // Initialize a HashMap HashMap<Integer, String> myMap = new HashMap<Integer, String>(); myMap.put( 2 , "three" ); myMap.put( 1 , "two" ); // Sort the HashMap by value List<Map.Entry<Integer, String>> sortedList = new ArrayList<Map.Entry<Integer, String>>(myMap.entrySet()); Collections.sort(sortedList, (kv1, kv2) -> kv1.getValue().compareTo(kv2.getValue())); // Print sorted dictionary System.out.print( "Sorted dictionary is : " ); for (Map.Entry<Integer, String> entry : sortedList) { System.out.print(entry.getKey() + ":" + entry.getValue() + " " ); } } } |
Sorted dictionary is : [(2, 'three'), (1, 'two')]
The time complexity of this program is O(n log n), where n is the size of the dictionary.
The space complexity is O(n), where n is the size of the dictionary.
Using items() alone: The method items() is used alone with two variables i.e., key and value to sort the dictionary by value.
Examples:
Input: my_dict = {‘c’: 3, ‘a’: 1, ‘d’: 4, ‘b’: 2}
Output: [(1, ‘a’), (2, ‘b’), (3, ‘c’), (4, ‘d’)]
Below is the implementation using method items():
Python3
# Python program to sort dictionary # by value using item function # Initialize a dictionary my_dict = { 'c' : 3 , 'a' : 1 , 'd' : 4 , 'b' : 2 } # Sorting dictionary sorted_dict = sorted ([(value, key) for (key, value) in my_dict.items()]) # Print sorted dictionary print ( "Sorted dictionary is :" ) print (sorted_dict) |
Javascript
// Initialize a dictionary const my_dict = { 'c' : 3, 'a' : 1, 'd' : 4, 'b' : 2 }; // Sorting dictionary const sorted_dict = Object.entries(my_dict) .sort((a, b) => a[1] - b[1]) .map(entry => [entry[1], entry[0]]); // Print sorted dictionary console.log( "Sorted dictionary is :" ); console.log(sorted_dict); // This code is contributed by Prince Kumar |
Sorted dictionary is : [(1, 'a'), (2, 'b'), (3, 'c'), (4, 'd')]
Time Complexity: O(n log n)
Space Complexity: O(n)
Using sorted() and get(): The method get() returns the value for the given key, if present in the dictionary. If not, then it will return None.
Examples:
Input: my_dict = {‘red’:’#FF0000′, ‘green’:’#008000′, ‘black’:’#000000′, ‘white’:’#FFFFFF’}
Output:
black #000000
green #008000
red #FF0000
white #FFFFFF
Below is the implementation using sorted() and get() method:
Python3
# Python program to sort dictionary # by value using sorted() and get() # Initialize a dictionary my_dict = { 'red' : '# FF0000' , 'green' : '# 008000' , 'black' : '# 000000' , 'white' : '# FFFFFF' } # Sort and print dictionary print ( "Sorted dictionary is :" ) for w in sorted (my_dict, key = my_dict.get): print (w, my_dict[w]) |
Sorted dictionary is : black # 000000 green # 008000 red # FF0000 white # FFFFFF
Time complexity: O(nlogn) – sorting the dictionary using the sorted() function takes nlogn time,
Auxiliary space: O(n) – creating a new list of keys in sorted order takes O(n) space.
Using itemgetter from operator:
The method itemgetter(n) constructs a callable that assumes an iterable object as input, and fetches the n-th element out of it.
Examples
Input:
my_dict = {‘a’: 23, ‘g’: 67, ‘e’: 12, 45: 90}
Output:
[(‘e’, 12), (‘a’, 23), (‘g’, 67), (45, 90)]
Below is the python program to sort the dictionary using itemgetter():
Python3
# Python program to sort dictionary # by value using itemgetter() function # Importing OrderedDict import operator # Initialize a dictionary my_dict = { 'a' : 23 , 'g' : 67 , 'e' : 12 , 45 : 90 } # Sorting dictionary sorted_dict = sorted (my_dict.items(), \ key = operator.itemgetter( 1 )) # Printing sorted dictionary print ( "Sorted dictionary is :" ) print (sorted_dict) |
Sorted dictionary is : [('e', 12), ('a', 23), ('g', 67), (45, 90)]
Time complexity: O(n log n)
The time complexity of sorting a dictionary using the itemgetter() function is O(n log n). This is because the itemgetter() function must traverse through the dictionary and compare each element to determine the sorting order. Since comparing each element is an O(n) operation, and sorting is an O(log n) operation, the overall time complexity is O(n log n).
Space complexity: O(n)
The space complexity of sorting a dictionary using the itemgetter() function is O(n). This is because the itemgetter() function must create a new list containing all of the elements of the dictionary, which requires O(n) space.
Using OrderedDict from collections: The OrderedDict is a standard library class, which is located in the collections module. OrderedDict maintains the orders of keys as inserted.
Examples:
Input: my_dict = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
Output: [(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)]
Below is the implementation using Ordered Dict:
Python3
# Python program to sort dictionary # by value using OrderedDict # Import OrderedDict from collections import OrderedDict # Initialize a dictionary my_dict = { 1 : 2 , 3 : 4 , 4 : 3 , 2 : 1 , 0 : 0 } # Sort dictionary sorted_dict = OrderedDict( sorted (\ my_dict.items(), key = lambda x: x[ 1 ])) # Print the sorted dictionary print ( "Sorted dictionary is :" ) print (sorted_dict) |
Sorted dictionary is : OrderedDict([(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)])
Time complexity: The time complexity of this program is O(n log n), where n is the size of the dictionary.
Space complexity: The space complexity of this program is O(n), where n is the size of the dictionary.
Using Counter from collections: The counter is an unordered collection where elements are stored as Dict keys and their count as dict value. Counter elements count can be positive, zero or negative integers.
Examples:
Input: my_dict = {‘hello’: 1, ‘python’: 5, ‘world’: 3}
Output: [(‘hello’, 1), (‘world’, 3), (‘python’, 5)]
Below is the implementation using Counter from collections:
Python3
# Python program to sort dictionary # by value using OrderedDict # Import Counter from collections import Counter # Initialize a dictionary my_dict = { 'hello' : 1 , 'python' : 5 , 'world' : 3 } # Sort and print the dictionary sorted_dict = Counter(my_dict) print ( "Sorted dictionary is :" ) print (sorted_dict.most_common()[:: - 1 ]) |
Sorted dictionary is : [('hello', 1), ('world', 3), ('python', 5)]
Reverse Sorting Dictionary by values: The same syntax for both ascending and descending ordered sorting. For reverse sorting, the idea is to use reverse = true. with the function sorted().
Examples:
Input:
my_dict = {‘red’:’#FF0000′,
‘green’:’#008000′,
‘black’:’#000000′,
‘white’:’#FFFFFF’}
Output:
black #000000
green #008000
red #FF0000
white #FFFFFF
Below is the implementation using Reverse Sorting Dictionary by values:
Python3
# Python program to sort dictionary # by value using sorted setting # reverse parameter to true # Initialize a dictionary my_dict = { 'red' : '# FF0000' , 'green' : '# 008000' , 'black' : '# 000000' , 'white' : '# FFFFFF' } # Sort and print the dictionary print ( "Sorted dictionary is :" ) for w in sorted (my_dict, key = my_dict.get, \ reverse = True ): print (w, my_dict[w]) |
Sorted dictionary is : white # FFFFFF red # FF0000 green # 008000 black # 000000