Given a Strings List, extract characters in index range spanning entire Strings list.
Input : test_list = ["neveropen", "is", "best", "for", "Lazyroar"], strt, end = 14, 20 Output : sbest Explanation : Once concatenated, 14 - 20 range is extracted.
Input : test_list = ["neveropen", "is", "best", "for", "Lazyroar"], strt, end = 11, 20 Output : sbesbest Explanation : Once concatenated, 11 – 20 range is extracted.
Method 1 : Using join() + list comprehension
In this, we perform concatenation of all the strings using join() and list comprehension, and post that, the required character range is extracted.
Python3
# initializing list test_list = [ "neveropen" , "is" , "best" , "for" , "Lazyroar" ] # printing original list print ( "The original list is : " + str (test_list)) # initializing char range strt, end = 14 , 30 # strt and end used to get desired characters res = ''.join([sub for sub in test_list])[strt : end] # printing result print ( "Range characters : " + str (res)) |
The original list is : ['neveropen', 'is', 'best', 'for', 'Lazyroar'] Range characters : sbestforLazyroar
Time Complexity: O(n) where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n) additional space of size n is created where n is the number of elements in the list “test_list”.
Method 2: Using chain.from_iterable() + join()
In this, we perform the task of flattening of characters using chain.from_iterable(), after that join() is used for concatenation of all strings, and indices are extracted in range.
Python3
# import module from itertools import chain # initializing list test_list = [ "neveropen" , "is" , "best" , "for" , "Lazyroar" ] # printing original list print ( "The original list is : " + str (test_list)) # initializing char range strt, end = 14 , 30 # strt and end used to get desired characters res = ''.join(chain.from_iterable(test_list))[strt : end] # printing result print ( "Range characters : " + str (res)) |
The original list is : ['neveropen', 'is', 'best', 'for', 'Lazyroar'] Range characters : sbestforLazyroar
Time Complexity: O(n)
Space Complexity: O(n)
Approach 3: Using reduce() + join()
In this approach, we use the reduce() function from the functools module to perform the concatenation of all strings in the list. This method concatenates all strings by successively calling the lambda function.
Python3
# Approach 3: Using reduce() + join() # import module from functools import reduce # initializing list test_list = [ "neveropen" , "is" , "best" , "for" , "Lazyroar" ] # printing original list print ( "The original list is : " + str (test_list)) # initializing char range strt, end = 14 , 30 # using reduce to perform concatenation of all strings res = reduce ( lambda x, y: x + y, test_list)[strt : end] # strt and end used to get desired characters # printing result print ( "Range characters : " + str (res)) |
The original list is : ['neveropen', 'is', 'best', 'for', 'Lazyroar'] Range characters : sbestforLazyroar
Time complexity: O(n), where ‘n’ is the total number of characters in the given list.
Auxiliary space: O(m), where ‘m’ is the length of the desired substring.
Approach 4: use a simple for loop to iterate through the strings and concatenate them.
Step-by-step approach:
- Initialize a variable ‘result’ as an empty string to store the concatenated strings.
- Iterate through each string in the given list ‘test_list’ using a for loop.
- Use the ‘+= operator’ to concatenate each string with the ‘result’ variable.
- Use string slicing to get the desired characters from the concatenated string.
- Print the desired characters.
Python3
# initializing list test_list = [ "neveropen" , "is" , "best" , "for" , "Lazyroar" ] # printing original list print ( "The original list is : " + str (test_list)) # initializing char range strt, end = 14 , 30 # initializing result variable result = "" # concatenate all strings in test_list for string in test_list: result + = string # get desired characters using string slicing res = result[strt:end] # printing result print ( "Range characters : " + str (res)) |
The original list is : ['neveropen', 'is', 'best', 'for', 'Lazyroar'] Range characters : sbestforLazyroar
Time complexity: O(n), where ‘n’ is the total number of characters in the given list.
Auxiliary space: O(m), where ‘m’ is the length of the desired substring.