With the help of numpy.ndarray.__le__() method of Numpy, We can find that which element in an array is less than or equal to the value which is provided in the parameter. It will return you numpy array with boolean type having only values True and False.
Syntax: ndarray.__le__($self, value, /) Return: self<=value
Example #1 : In this example we can see that after applying numpy.__le__(), we get the simple boolean array that can tell us which element in an array is less than or equal to that of provided parameter.
Python3
# import the important module in pythonimport numpy as np# make an array with numpygfg = np.array([1, 2, 3, 4, 5, 6])# applying numpy.__le__() methodprint(gfg.__le__(4)) |
Output:
[ True True True True False False]
Example #2 :
Python3
# import the important module in pythonimport numpy as np# make an array with numpygfg = np.array([[1, 2, 3, 4, 5, 6], [6, 5, 4, 3, 2, 1]])# applying numpy.__le__() methodprint(gfg.__le__(4)) |
Output:
[[ True True True True False False] [False False True True True True]]
